dr-w
dr-w
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mass % = mass H2O / mass total x 100% = (1.22g - 0.77g) / (1.22g) x 100% = ___ %
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considering that "CH2" would have a -2 charge and 2 unshared electron pairs, it would be polar if it existed.
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CC equation... ln(P1 / P2) = -ΔHvap / R) x (1/T1 - 1/T2) rearranging.. ln(P1) - ln(P2) = (-ΔHvap / R) x (1/T1) + (ΔHvap / R) x (1/T2) rearranging... ln(P1) = (-ΔHvap / R) x (1/T1) + (ΔHvap / R) x (1/T2) + ln(P2) and if we assume (T2,P2…
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so.. this is basically just a conversion problem.. And conversions are best done by what technique? that's right "factor label method".. aka.. "Dmensional analsis" and we apply DA like this (1).. sort through the problem and…
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Penny candy rules!
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Penny candy rules!
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divide 478 ppm by molar mass in g/mole ********** ppm is parts per million if that is ppm by mass.. and it is say ppm A in a mixture then... 1 ppm A = 1 g A / 10^6 g mixture (1 g A / 10^6 g mixture) x (1 mole A / X g A) x (10^6 µm / mol…
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Seems a bit silly for chemteam to say "that's a very good score. Go eat ice cream" without having any basis to back it up. So let's look at your score compared to other students. ********* from collegeboard.com, the grade distributi…
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Seems a bit silly for chemteam to say "that's a very good score. Go eat ice cream" without having any basis to back it up. So let's look at your score compared to other students. ********* from collegeboard.com, the grade distributi…
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divide 478 ppm by molar mass in g/mole ********** ppm is parts per million if that is ppm by mass.. and it is say ppm A in a mixture then... 1 ppm A = 1 g A / 10^6 g mixture (1 g A / 10^6 g mixture) x (1 mole A / X g A) x (10^6 µm / mol…
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divide 478 ppm by molar mass in g/mole ********** ppm is parts per million if that is ppm by mass.. and it is say ppm A in a mixture then... 1 ppm A = 1 g A / 10^6 g mixture (1 g A / 10^6 g mixture) x (1 mole A / X g A) x (10^6 µm / mol…
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Penny candy rules!
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Penny candy rules!
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so.. this is basically just a conversion problem.. And conversions are best done by what technique? that's right "factor label method".. aka.. "Dmensional analsis" and we apply DA like this (1).. sort through the problem and…
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so.. this is basically just a conversion problem.. And conversions are best done by what technique? that's right "factor label method".. aka.. "Dmensional analsis" and we apply DA like this (1).. sort through the problem and…
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so.. this is basically just a conversion problem.. And conversions are best done by what technique? that's right "factor label method".. aka.. "Dmensional analsis" and we apply DA like this (1).. sort through the problem and…
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so.. this is basically just a conversion problem.. And conversions are best done by what technique? that's right "factor label method".. aka.. "Dmensional analsis" and we apply DA like this (1).. sort through the problem and…
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CC equation... ln(P1 / P2) = -ΔHvap / R) x (1/T1 - 1/T2) rearranging.. ln(P1) - ln(P2) = (-ΔHvap / R) x (1/T1) + (ΔHvap / R) x (1/T2) rearranging... ln(P1) = (-ΔHvap / R) x (1/T1) + (ΔHvap / R) x (1/T2) + ln(P2) and if we assume (T2,P2…
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CC equation... ln(P1 / P2) = -ΔHvap / R) x (1/T1 - 1/T2) rearranging.. ln(P1) - ln(P2) = (-ΔHvap / R) x (1/T1) + (ΔHvap / R) x (1/T2) rearranging... ln(P1) = (-ΔHvap / R) x (1/T1) + (ΔHvap / R) x (1/T2) + ln(P2) and if we assume (T2,P2…
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mass % = mass H2O / mass total x 100% = (1.22g - 0.77g) / (1.22g) x 100% = ___ %