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trevor-h

trevor-h

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trevor-h
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  • You should bear in mind that any fines ASDA collect from this will go to charity. They are not trying to make money for themselves out of this (which would have put me against this idea), only to make shopping easier for the disabled and parents…
  • 1 mol of anything contains 6.022*10^23 molecules You have 2.58*10^24 molecules Moles = ( 2.58*10^24)/(6.022*10^23) = 4.28 moles C2H6O
  • 1 mol of anything contains 6.022*10^23 molecules You have 2.58*10^24 molecules Moles = ( 2.58*10^24)/(6.022*10^23) = 4.28 moles C2H6O
  • A 0.200 M solution of a weak base in water has a pH = 10.40 at 25 C. Calculate the value of Kb for this base. I know that pH = pKa + log[A/HA] but I cant figure out the answer. Answer: You do not have a buffer solution therefore you cannot use the…
  • A 0.200 M solution of a weak base in water has a pH = 10.40 at 25 C. Calculate the value of Kb for this base. I know that pH = pKa + log[A/HA] but I cant figure out the answer. Answer: You do not have a buffer solution therefore you cannot use the…
  • A 0.200 M solution of a weak base in water has a pH = 10.40 at 25 C. Calculate the value of Kb for this base. I know that pH = pKa + log[A/HA] but I cant figure out the answer. Answer: You do not have a buffer solution therefore you cannot use the…
  • A 0.200 M solution of a weak base in water has a pH = 10.40 at 25 C. Calculate the value of Kb for this base. I know that pH = pKa + log[A/HA] but I cant figure out the answer. Answer: You do not have a buffer solution therefore you cannot use the…
  • Of course you are correct. Take the following example: In order to prepare a 1M solution of (as an example) NaOH, you would take 40g NaOH and dissolve to a volume of 1 litre. Now divide 40g by 1000 and you have 40mg Now divide 1 litre by 1000 a…
  • Look at the balanced equation: This tells you that 1 mol of C4H10 will produce 5 mol H2O How many mol of C4H10 do you have in 7g ? Molar mass C4H10 = 4*12 + 10*1 = 58g/mol Moles in 7g = 7/58 = 0.121 mol C4H10 This will produce 0.121*5 = 0…
  • Look at the balanced equation: This tells you that 1 mol of C4H10 will produce 5 mol H2O How many mol of C4H10 do you have in 7g ? Molar mass C4H10 = 4*12 + 10*1 = 58g/mol Moles in 7g = 7/58 = 0.121 mol C4H10 This will produce 0.121*5 = 0…
  • Look at the balanced equation: This tells you that 1 mol of C4H10 will produce 5 mol H2O How many mol of C4H10 do you have in 7g ? Molar mass C4H10 = 4*12 + 10*1 = 58g/mol Moles in 7g = 7/58 = 0.121 mol C4H10 This will produce 0.121*5 = 0…
  • Of course you are correct. Take the following example: In order to prepare a 1M solution of (as an example) NaOH, you would take 40g NaOH and dissolve to a volume of 1 litre. Now divide 40g by 1000 and you have 40mg Now divide 1 litre by 1000 a…
  • Of course you are correct. Take the following example: In order to prepare a 1M solution of (as an example) NaOH, you would take 40g NaOH and dissolve to a volume of 1 litre. Now divide 40g by 1000 and you have 40mg Now divide 1 litre by 1000 a…
  • A 0.200 M solution of a weak base in water has a pH = 10.40 at 25 C. Calculate the value of Kb for this base. I know that pH = pKa + log[A/HA] but I cant figure out the answer. Answer: You do not have a buffer solution therefore you cannot use the…
  • A 0.200 M solution of a weak base in water has a pH = 10.40 at 25 C. Calculate the value of Kb for this base. I know that pH = pKa + log[A/HA] but I cant figure out the answer. Answer: You do not have a buffer solution therefore you cannot use the…
  • 1 mol of anything contains 6.022*10^23 molecules You have 2.58*10^24 molecules Moles = ( 2.58*10^24)/(6.022*10^23) = 4.28 moles C2H6O
  • 1 mol of anything contains 6.022*10^23 molecules You have 2.58*10^24 molecules Moles = ( 2.58*10^24)/(6.022*10^23) = 4.28 moles C2H6O