Calculate the number of grams of H2O produced when 7g of C4H10 is burnt in oxygen
Please can you explain in simple terms how you worked this out
Thank you so much
Look at the balanced equation: This tells you that 1 mol of C4H10 will produce 5 mol H2O
How many mol of C4H10 do you have in 7g ?
Molar mass C4H10 = 4*12 + 10*1 = 58g/mol
Moles in 7g = 7/58 = 0.121 mol C4H10
This will produce 0.121*5 = 0.605 mol H2O
Mo9lar mass of H2O = 18g/mol
Mass of 0.605 mol H2O = 0.605*18 = 10.89g H2O produced
You can have only 1 significant figure in the answer - 10g H2O produced.
Basically, convert the amount of grams of C4H10 to moles, compare the mole ratio between C4H10 and H2O, and convert the amount of moles of H2O to grams.
1mol C4H10 = 4*12.0107g + 10*1.00794g = 58.1222g C4H10
7g of C4H10 * 1mol of C4H10/58.1222g of C4H10 = 0.1204359092mol of C4H10
For every mole of C4H10 reacting should produce 5 moles of H2O; therefore, the ratio between moles of H2O and C4H10 is 5 to 1.
0.1204359092mol of C4H10 * 5mol of H2O/1mol of C4H10 = 0.6021795459mol of H2O
1mol H2O = 2*1.00794g + 15.9994g = 18.01528g H2O
0.6021795459mol of H2O * 18.01528g of H2O/1mol of H2O = 10.84843313g of H2O
Hope this helps
Equation: C4H10 + 6.5O2 â 4CO2 + 5H2O
moles of:......1..........6.5............4.............5
mass shown:58 g....6.5x16 g...4x44g.....5x18 g
.......................58 g 208 g......176 g ......108 g
? g H2O = 7 g C4H10 x 108 g H2O / 58 g C4H10 = 13 g H2O
Comments
Look at the balanced equation: This tells you that 1 mol of C4H10 will produce 5 mol H2O
How many mol of C4H10 do you have in 7g ?
Molar mass C4H10 = 4*12 + 10*1 = 58g/mol
Moles in 7g = 7/58 = 0.121 mol C4H10
This will produce 0.121*5 = 0.605 mol H2O
Mo9lar mass of H2O = 18g/mol
Mass of 0.605 mol H2O = 0.605*18 = 10.89g H2O produced
You can have only 1 significant figure in the answer - 10g H2O produced.
Basically, convert the amount of grams of C4H10 to moles, compare the mole ratio between C4H10 and H2O, and convert the amount of moles of H2O to grams.
1mol C4H10 = 4*12.0107g + 10*1.00794g = 58.1222g C4H10
7g of C4H10 * 1mol of C4H10/58.1222g of C4H10 = 0.1204359092mol of C4H10
For every mole of C4H10 reacting should produce 5 moles of H2O; therefore, the ratio between moles of H2O and C4H10 is 5 to 1.
0.1204359092mol of C4H10 * 5mol of H2O/1mol of C4H10 = 0.6021795459mol of H2O
1mol H2O = 2*1.00794g + 15.9994g = 18.01528g H2O
0.6021795459mol of H2O * 18.01528g of H2O/1mol of H2O = 10.84843313g of H2O
Hope this helps
Equation: C4H10 + 6.5O2 â 4CO2 + 5H2O
moles of:......1..........6.5............4.............5
mass shown:58 g....6.5x16 g...4x44g.....5x18 g
.......................58 g 208 g......176 g ......108 g
? g H2O = 7 g C4H10 x 108 g H2O / 58 g C4H10 = 13 g H2O