sahsjing
sahsjing
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x^4 - 8x^2 + 8 = (x^2-4)^2 - 8 = (x^2-4-sqrt(8))(x^2-4+sqrt(8)) x-int = +/-sqrt(4+sqrt(8)) and x-int = +/-sqrt(4-sqrt(8))
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x^4 - 8x^2 + 8 = (x^2-4)^2 - 8 = (x^2-4-sqrt(8))(x^2-4+sqrt(8)) x-int = +/-sqrt(4+sqrt(8)) and x-int = +/-sqrt(4-sqrt(8))
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Since lne^(1/2) = 1/2, 1/2 - ln 7 = lne^(1/2) - ln7 = ln[e^(1/2)/7]
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Since lne^(1/2) = 1/2, 1/2 - ln 7 = lne^(1/2) - ln7 = ln[e^(1/2)/7]
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The three terms can be written as x-d, x, x+d 3x = 3.5 x = 3.5/3, the middle term. So, it is impossible to have such an AP.
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The three terms can be written as x-d, x, x+d 3x = 3.5 x = 3.5/3, the middle term. So, it is impossible to have such an AP.
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sin 3x = sum from n=0 to infiinity is ( (-1)^n*((3x)^(2n+1)/(2n+1)!) integral from 0 to x of sin t^2 dt = integral from 0 to x of ( (-1)^n*((t^2)^(2n+1)/(2n+1)!) dt = [(-1)^n/(4n+3)]t^(4n+3)/(2n+1)! from 0 to x = [(-1)^n/(4n+3)]x^(4n+3)/(2n+1…
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y = a/b ------ Attn: Neglect lower degree terms.
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y = a/b ------ Attn: Neglect lower degree terms.
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(1-cos^2 theta)(1+cot^2 theta) = sin^2 theta csc^2 theta = 1 ----------- Attn: sinx cscx = 1
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L = 2W......(1) 2(L+W) = 24......(2) Plug in (1) into (2), 2W+W = 24/2 = 12 W = 4 L = 2W = 8 Answer: The length is 8 ft.
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540/20 = 27, the average of the first 20 terms 1260/30 = 42, the average of the first 30 terms d = (42-27)/5 = 3, the common difference [a(1)+a(1)+(20-1)*3]*20/2 = 540 a(1) = -3/2 -------- Get it done in the simplest way is what you always s…
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540/20 = 27, the average of the first 20 terms 1260/30 = 42, the average of the first 30 terms d = (42-27)/5 = 3, the common difference [a(1)+a(1)+(20-1)*3]*20/2 = 540 a(1) = -3/2 -------- Get it done in the simplest way is what you always s…
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Let the length of the segment be L and let h1 and h be the partial height and the total height. (L+7)h1 = (1/2)(1+7)h, balanced by areas h1/(7-L) = h/(7-1), proportionality Simplify and combine the two equations, (L+7)/4 = h/h1 = 6/(7-L) …
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Let the length of the segment be L and let h1 and h be the partial height and the total height. (L+7)h1 = (1/2)(1+7)h, balanced by areas h1/(7-L) = h/(7-1), proportionality Simplify and combine the two equations, (L+7)/4 = h/h1 = 6/(7-L) …
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Let the length of the segment be L and let h1 and h be the partial height and the total height. (L+7)h1 = (1/2)(1+7)h, balanced by areas h1/(7-L) = h/(7-1), proportionality Simplify and combine the two equations, (L+7)/4 = h/h1 = 6/(7-L) …
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Let the length of the segment be L and let h1 and h be the partial height and the total height. (L+7)h1 = (1/2)(1+7)h, balanced by areas h1/(7-L) = h/(7-1), proportionality Simplify and combine the two equations, (L+7)/4 = h/h1 = 6/(7-L) …
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cos(x+y)*cos(x-y) = (1/2)[cos(2x) + cos(2y)] = (1/2)[2cos^2x - 1 + 1 - 2sin^2y] = cos^2x - sin^2y ---------- Ideas: 2cosAcosB = cos(A+B) + cos(A-B)
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cos(x+y)*cos(x-y) = (1/2)[cos(2x) + cos(2y)] = (1/2)[2cos^2x - 1 + 1 - 2sin^2y] = cos^2x - sin^2y ---------- Ideas: 2cosAcosB = cos(A+B) + cos(A-B)
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Let the length of the segment be L and let h1 and h be the partial height and the total height. (L+7)h1 = (1/2)(1+7)h, balanced by areas h1/(7-L) = h/(7-1), proportionality Simplify and combine the two equations, (L+7)/4 = h/h1 = 6/(7-L) …
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Let the length of the segment be L and let h1 and h be the partial height and the total height. (L+7)h1 = (1/2)(1+7)h, balanced by areas h1/(7-L) = h/(7-1), proportionality Simplify and combine the two equations, (L+7)/4 = h/h1 = 6/(7-L) …
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540/20 = 27, the average of the first 20 terms 1260/30 = 42, the average of the first 30 terms d = (42-27)/5 = 3, the common difference [a(1)+a(1)+(20-1)*3]*20/2 = 540 a(1) = -3/2 -------- Get it done in the simplest way is what you always s…
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540/20 = 27, the average of the first 20 terms 1260/30 = 42, the average of the first 30 terms d = (42-27)/5 = 3, the common difference [a(1)+a(1)+(20-1)*3]*20/2 = 540 a(1) = -3/2 -------- Get it done in the simplest way is what you always s…
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540/20 = 27, the average of the first 20 terms 1260/30 = 42, the average of the first 30 terms d = (42-27)/5 = 3, the common difference [a(1)+a(1)+(20-1)*3]*20/2 = 540 a(1) = -3/2 -------- Get it done in the simplest way is what you always s…
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540/20 = 27, the average of the first 20 terms 1260/30 = 42, the average of the first 30 terms d = (42-27)/5 = 3, the common difference [a(1)+a(1)+(20-1)*3]*20/2 = 540 a(1) = -3/2 -------- Get it done in the simplest way is what you always s…
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L = 2W......(1) 2(L+W) = 24......(2) Plug in (1) into (2), 2W+W = 24/2 = 12 W = 4 L = 2W = 8 Answer: The length is 8 ft.
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y = a/b ------ Attn: Neglect lower degree terms.
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The three terms can be written as x-d, x, x+d 3x = 3.5 x = 3.5/3, the middle term. So, it is impossible to have such an AP.
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Since lne^(1/2) = 1/2, 1/2 - ln 7 = lne^(1/2) - ln7 = ln[e^(1/2)/7]
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x^4 - 8x^2 + 8 = (x^2-4)^2 - 8 = (x^2-4-sqrt(8))(x^2-4+sqrt(8)) x-int = +/-sqrt(4+sqrt(8)) and x-int = +/-sqrt(4-sqrt(8))