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Which is the equation of the line that passes through (10, 6) and (5, 3)? Slope of the line (m) = (6 - 3)/(10 - 5) = 3/5 Equation of line is y = (3/5)x + c Substitute either set of coordinate points to determine c 6 = (3/5)*10 + c c = 0 Eq…
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Which is the equation of the line that passes through (10, 6) and (5, 3)? Slope of the line (m) = (6 - 3)/(10 - 5) = 3/5 Equation of line is y = (3/5)x + c Substitute either set of coordinate points to determine c 6 = (3/5)*10 + c c = 0 Eq…
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1.) A cleaning company has monthly fixed costs of $9000 for its facilities and it costs $100 per house for each house that it cleans. How many houses must the company clean each month to have an average cost per house of $170? Let x = number of hou…
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1.) A cleaning company has monthly fixed costs of $9000 for its facilities and it costs $100 per house for each house that it cleans. How many houses must the company clean each month to have an average cost per house of $170? Let x = number of hou…
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Since both sources provide crude oil that is hydrocarbons and you do not differentiate between the two sources, it doesn't matter whether you mix the two or take it all from one of the two sources. I think you are missing some information.
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R(p)= -4p^2 + 4000p dR(p)/dp = -8p + 4000 At max or min dR(p)/dp = 0 0 = -8p + 4000 p = 500 R(500) = -4(500^2) + 4000*500 d2R(p)/dp^2 = -8 Negative means that the value found for dR(p) is a maximum
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R(p)= -4p^2 + 4000p dR(p)/dp = -8p + 4000 At max or min dR(p)/dp = 0 0 = -8p + 4000 p = 500 R(500) = -4(500^2) + 4000*500 d2R(p)/dp^2 = -8 Negative means that the value found for dR(p) is a maximum
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product of (3x+7)*(7x-3) = 21x^2 - 9x +49x - 21 = 21x^2 + 40x - 21
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Let x = amount invested at 11% 1)...A1 = x(1.11) 2)...A2 = (5900 - x)(1.06) 2) ...A2 = 6254 - 1.06x Total return = 5900 + 509 = 6409 A1 + A2 = 6409 3) 6409 = 1.11x + 6254 - 1.06x 155 = 1.05x x = $147.62 invested at 11% $361.38 invested at 6…
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Let x = amount invested at 11% 1)...A1 = x(1.11) 2)...A2 = (5900 - x)(1.06) 2) ...A2 = 6254 - 1.06x Total return = 5900 + 509 = 6409 A1 + A2 = 6409 3) 6409 = 1.11x + 6254 - 1.06x 155 = 1.05x x = $147.62 invested at 11% $361.38 invested at 6…
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Let x = amount invested at 11% 1)...A1 = x(1.11) 2)...A2 = (5900 - x)(1.06) 2) ...A2 = 6254 - 1.06x Total return = 5900 + 509 = 6409 A1 + A2 = 6409 3) 6409 = 1.11x + 6254 - 1.06x 155 = 1.05x x = $147.62 invested at 11% $361.38 invested at 6…
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(4 + 5i) (5 + 5i) 20 + 20i + 25i - 25 45i -25 9i - 5 ---------- x ------------- = ----------------------------- = ---------- = -------- (5 - 5i) (5 + 5i) 25 + 25 …
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(4 + 5i) (5 + 5i) 20 + 20i + 25i - 25 45i -25 9i - 5 ---------- x ------------- = ----------------------------- = ---------- = -------- (5 - 5i) (5 + 5i) 25 + 25 …
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Let x = amount invested at 11% 1)...A1 = x(1.11) 2)...A2 = (5900 - x)(1.06) 2) ...A2 = 6254 - 1.06x Total return = 5900 + 509 = 6409 A1 + A2 = 6409 3) 6409 = 1.11x + 6254 - 1.06x 155 = 1.05x x = $147.62 invested at 11% $361.38 invested at 6…
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product of (3x+7)*(7x-3) = 21x^2 - 9x +49x - 21 = 21x^2 + 40x - 21
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Since both sources provide crude oil that is hydrocarbons and you do not differentiate between the two sources, it doesn't matter whether you mix the two or take it all from one of the two sources. I think you are missing some information.
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Which is the equation of the line that passes through (10, 6) and (5, 3)? Slope of the line (m) = (6 - 3)/(10 - 5) = 3/5 Equation of line is y = (3/5)x + c Substitute either set of coordinate points to determine c 6 = (3/5)*10 + c c = 0 Eq…