Algebra 2 help ASAP please?
I really need help on this one question i can't seem to figure out.
Which is the equation of the line that passes through (10, 6) and (5, 3)?
(Points : 3)
Option A: y= 1/5x + 3
Option B: y= -3/5x + 6
Option C: y= -1/5x + 4
Option 
y= 1/5x + 2
Comments
First, find the slope between the points
m = (y2 - y1) / (x2 - x1) = (3 - 6) / (5 - 10) = -3/-5 = 3/5
Right off the bat, we can see that none of the choices are correct. Let's go ahead and figure out the formula for the line anyway
y - k = m * (x - h)
(h , k) is a point that the line passes through
y - 6 = (3/5) * (x - 10)
5y - 30 = 3x - 30
5y = 3x
y = (3/5) * x
Which is the equation of the line that passes through (10, 6) and (5, 3)?
Slope of the line (m) = (6 - 3)/(10 - 5) = 3/5
Equation of line is y = (3/5)x + c
Substitute either set of coordinate points to determine c
6 = (3/5)*10 + c
c = 0
Equation is: y = (3/5)x or 5y = 3x
Answer: none of the above
--------------------------------------------