Select the product of (3x+7)*(7x-3)
is it 10x^2 +8x+4?
Thanks in advance ))))))))))))))))))))))))))
ME
product of (3x + 7) * (7x - 3)
= (3x+7)*(7x-3)
= 21x^2 - 9x + 49x - 21
= 21x^2 + 40x - 21 Ans.
product of (3x+7)*(7x-3) = 21x^2 - 9x +49x - 21 = 21x^2 + 40x - 21
(3x+7)*(7x-3)
=21x^2+40x-21 is not equal to 10x^2 +8x+4
so answer is NO...........
(3x+7)(7x-3)
= 21x^2 + 40x - 21
No
Answer is 21x^2 +40x - 21
21x^2+40x-21
21x^2-9x+49x-21
=21x^2+40x-21
))))))))))))))))))))))))))
Comments
product of (3x + 7) * (7x - 3)
= (3x+7)*(7x-3)
= 21x^2 - 9x + 49x - 21
= 21x^2 + 40x - 21 Ans.
product of (3x+7)*(7x-3) = 21x^2 - 9x +49x - 21 = 21x^2 + 40x - 21
(3x+7)*(7x-3)
=21x^2+40x-21 is not equal to 10x^2 +8x+4
so answer is NO...........
(3x+7)(7x-3)
= 21x^2 - 9x + 49x - 21
= 21x^2 + 40x - 21
No
Answer is 21x^2 +40x - 21
21x^2+40x-21
21x^2-9x+49x-21
=21x^2+40x-21