oldprof
oldprof
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First a bit of physics. Because the whole thing is frictionless, we can consider the entire system to be suspended in the air so that it looks like: o | \ | \ |....[] 4.4 [] 2.6 a) Clearly, as they are attached by the cord, both blocks…
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OK, in the S = 45 m, the RC loses QE = FS = 1/3 mgS of its energy between 1 and 2.. mg = W is the weight of the RC. At 1, TE = ke + pe = 1/2 mv^2 + mgH; where H = 35 m and v = 1.1 mps. At 2, TE = 1/2 mV^2 + mgh - QE; where h = 14 m. From the…
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When we have a pile on with bodies on top of each other, who has the most weight on top of them...the ones on the bottom or the ones on top of the pile? Same with air. There is more air piled on top of the lower altitudes than on top of the higher…
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When we have a pile on with bodies on top of each other, who has the most weight on top of them...the ones on the bottom or the ones on top of the pile? Same with air. There is more air piled on top of the lower altitudes than on top of the higher…
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I doubt you'll follow this, but.... dP = d(MV) = MdV + dM V = F dT dM = 0; so MdVC = F dTC = F dS MC INT(dV)|0 to C = F IN(dS)|0 to S MCC = FS = E MC^2 = E Mull this over and learn.
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If you use the right definition for "decay" yes, they can decay. But understand decay in the nuke sense does not mean to rot, like a rotting apple. It means the atom transmutes from one element into another element spontaneously. An…
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If you use the right definition for "decay" yes, they can decay. But understand decay in the nuke sense does not mean to rot, like a rotting apple. It means the atom transmutes from one element into another element spontaneously. An…
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Me, too. Why don't you take this question to the Math Category?
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Ah, but you missed one of the tricks of the trade. You define both bodies, e.g., planet and satellites, as one system. Hey, we do call it the solar "system." We define a system so that it is closed when we can. That simplifies a lot …
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Ah, but you missed one of the tricks of the trade. You define both bodies, e.g., planet and satellites, as one system. Hey, we do call it the solar "system." We define a system so that it is closed when we can. That simplifies a lot …
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That marble didn't roll the diameter; it rolled the semi circumference. So S = pi D/2 = Vavg T and Vavg = pi()*50/(2*10) = 7.853981634 = 7.85 cm/s ANS.
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The best way to picture this is with a picture, a so-called free-body diagram. But as Answers editing doesn't allow images, I draw one in our minds. Looking at the whirling rock and string from the side, we see that the cord forms the hypotenuse…
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My day began when I drove to work at about 7 AM to reach the National Lab where I was a young Research Associate. And as I worked in the lab's main administrative building, I occasionally rode up the elevator with Ed. Teller, the father of the H-bo…
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Humankind is wired to fight to live. That's how we, the species, survive. It is abnormal to want to die. If it were normal then the species would have died out long ago. But I agree. We can only offer so much therapy; otherwise it becomes pro…
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Humankind is wired to fight to live. That's how we, the species, survive. It is abnormal to want to die. If it were normal then the species would have died out long ago. But I agree. We can only offer so much therapy; otherwise it becomes pro…
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My day began when I drove to work at about 7 AM to reach the National Lab where I was a young Research Associate. And as I worked in the lab's main administrative building, I occasionally rode up the elevator with Ed. Teller, the father of the H-bo…
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The best way to picture this is with a picture, a so-called free-body diagram. But as Answers editing doesn't allow images, I draw one in our minds. Looking at the whirling rock and string from the side, we see that the cord forms the hypotenuse…
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The best way to picture this is with a picture, a so-called free-body diagram. But as Answers editing doesn't allow images, I draw one in our minds. Looking at the whirling rock and string from the side, we see that the cord forms the hypotenuse…
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The best way to picture this is with a picture, a so-called free-body diagram. But as Answers editing doesn't allow images, I draw one in our minds. Looking at the whirling rock and string from the side, we see that the cord forms the hypotenuse…
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The best way to picture this is with a picture, a so-called free-body diagram. But as Answers editing doesn't allow images, I draw one in our minds. Looking at the whirling rock and string from the side, we see that the cord forms the hypotenuse…
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The best way to picture this is with a picture, a so-called free-body diagram. But as Answers editing doesn't allow images, I draw one in our minds. Looking at the whirling rock and string from the side, we see that the cord forms the hypotenuse…
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The best way to picture this is with a picture, a so-called free-body diagram. But as Answers editing doesn't allow images, I draw one in our minds. Looking at the whirling rock and string from the side, we see that the cord forms the hypotenuse…
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That marble didn't roll the diameter; it rolled the semi circumference. So S = pi D/2 = Vavg T and Vavg = pi()*50/(2*10) = 7.853981634 = 7.85 cm/s ANS.
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Ah, but you missed one of the tricks of the trade. You define both bodies, e.g., planet and satellites, as one system. Hey, we do call it the solar "system." We define a system so that it is closed when we can. That simplifies a lot …
-
Ah, but you missed one of the tricks of the trade. You define both bodies, e.g., planet and satellites, as one system. Hey, we do call it the solar "system." We define a system so that it is closed when we can. That simplifies a lot …
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Ah, but you missed one of the tricks of the trade. You define both bodies, e.g., planet and satellites, as one system. Hey, we do call it the solar "system." We define a system so that it is closed when we can. That simplifies a lot …
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Me, too. Why don't you take this question to the Math Category?
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If you use the right definition for "decay" yes, they can decay. But understand decay in the nuke sense does not mean to rot, like a rotting apple. It means the atom transmutes from one element into another element spontaneously. An…
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I doubt you'll follow this, but.... dP = d(MV) = MdV + dM V = F dT dM = 0; so MdVC = F dTC = F dS MC INT(dV)|0 to C = F IN(dS)|0 to S MCC = FS = E MC^2 = E Mull this over and learn.
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When we have a pile on with bodies on top of each other, who has the most weight on top of them...the ones on the bottom or the ones on top of the pile? Same with air. There is more air piled on top of the lower altitudes than on top of the higher…