eugene
eugene
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1. V = 4/3 πr^3 3V/4π = r^3 (multiply both sides by 3/4π) (3V/4π)^(1/3) = r (take cube roots on both sides). 2. E = 1/2 mv^2 + 1/2 kx^2 E - 1/2 kx^2 = 1/2 mv^2 (subtract 1/2 kx^2 from both sides) 2E/m - kx^2 = v^2 (multiply both s…
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1. V = 4/3 πr^3 3V/4π = r^3 (multiply both sides by 3/4π) (3V/4π)^(1/3) = r (take cube roots on both sides). 2. E = 1/2 mv^2 + 1/2 kx^2 E - 1/2 kx^2 = 1/2 mv^2 (subtract 1/2 kx^2 from both sides) 2E/m - kx^2 = v^2 (multiply both s…
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-la/R^2 - mg = ma -mg = ma + la/R^2 (Add both sides by la/R^2) -mg = a(m + l/R^2) (Factor the a on the right-hand side) -g = a(1 + l/mR^2) (Divide both sides by m) -g/(1 + l/mR^2) = a (Divide both sides by 1 + l/mR^2).
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This Site Might Help You. RE: Monologue from a play for drama class? Ok so I have to do a drama monologue from a play ONLY. I was researching and didn't find anything great. What i'm looking for is something more of a comedy, bu…
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Mis preocupaciones por el vivir diario.........trabajo, finanzas, en fin tantas cosas que tenemos en nuestras vidas cada día.
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First I'll show that (im T)⊥ = ker T*. Since dim (im T)⊥ = dim V - dim (im T) = dim ker T, this will prove that dim ker T = dim ker T*. Let v be an element of (im T)⊥. Then <v, Tu> = 0 for all u in V. So <T*(v), u> = <v, Tu> …
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True cuz it cant b false
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You can 1. click it and click "SPAM" button 2. create a filter (top of gmail near the search button) that targets that source address Option 2 is better
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Stand on a podium, and argue with everyone in the vicinity. Congratulations you just maturbated everyone in the room, go home and tell your entire family the good news! It feels very good, it lets everyone know that you're the boss!
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Use the identity e^(x + y) = e^x * e^y to get ∫[0,1] e^(x + y) dy = e^y ∫[0,1] e^x dx = e^y * e^x (from x = 0 to 1) = e^y * (e - 1). Then ∫[0,1] ∫[0,1] e^(x + y) dy dx = ∫[0,1] e^y * (e - 1) dy = (e - 1) ∫[0,1] e^y dy = (e - 1)(e - 1) = (e - …
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Yes. Let d = gcd(m,n). Then d|m and d|n. Since r = n - qm, it follows that d|r. On the other hand, since r|m, r|(qm + r) and therefore r|n. Since r|m and r|n, r|d. Since d|r and r|d, r = +/- d.
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Yes. Let d = gcd(m,n). Then d|m and d|n. Since r = n - qm, it follows that d|r. On the other hand, since r|m, r|(qm + r) and therefore r|n. Since r|m and r|n, r|d. Since d|r and r|d, r = +/- d.
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Use the identity e^(x + y) = e^x * e^y to get ∫[0,1] e^(x + y) dy = e^y ∫[0,1] e^x dx = e^y * e^x (from x = 0 to 1) = e^y * (e - 1). Then ∫[0,1] ∫[0,1] e^(x + y) dy dx = ∫[0,1] e^y * (e - 1) dy = (e - 1) ∫[0,1] e^y dy = (e - 1)(e - 1) = (e - …
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Use the identity e^(x + y) = e^x * e^y to get ∫[0,1] e^(x + y) dy = e^y ∫[0,1] e^x dx = e^y * e^x (from x = 0 to 1) = e^y * (e - 1). Then ∫[0,1] ∫[0,1] e^(x + y) dy dx = ∫[0,1] e^y * (e - 1) dy = (e - 1) ∫[0,1] e^y dy = (e - 1)(e - 1) = (e - …
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Stand on a podium, and argue with everyone in the vicinity. Congratulations you just maturbated everyone in the room, go home and tell your entire family the good news! It feels very good, it lets everyone know that you're the boss!
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You can 1. click it and click "SPAM" button 2. create a filter (top of gmail near the search button) that targets that source address Option 2 is better
-
You can 1. click it and click "SPAM" button 2. create a filter (top of gmail near the search button) that targets that source address Option 2 is better
-
True cuz it cant b false
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Mis preocupaciones por el vivir diario.........trabajo, finanzas, en fin tantas cosas que tenemos en nuestras vidas cada día.
-
-la/R^2 - mg = ma -mg = ma + la/R^2 (Add both sides by la/R^2) -mg = a(m + l/R^2) (Factor the a on the right-hand side) -g = a(1 + l/mR^2) (Divide both sides by m) -g/(1 + l/mR^2) = a (Divide both sides by 1 + l/mR^2).