Algebra problem (-I*a)/R^2 - m*g = m*a solve for a?

saboohissaboohis
in Science & Mathematics

I know the answer is a = - g/ (1 + I/mR^2) but I dont know how to get there?

Comments

  • eugeneeugene

    -la/R^2 - mg = ma

    -mg = ma + la/R^2 (Add both sides by la/R^2)

    -mg = a(m + l/R^2) (Factor the a on the right-hand side)

    -g = a(1 + l/mR^2) (Divide both sides by m)

    -g/(1 + l/mR^2) = a (Divide both sides by 1 + l/mR^2).

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