battleaxe
battleaxe
About
- Username
- battleaxe
- Joined
- Visits
- 0
- Last Active
- Roles
- Member
Comments
-
1, 5 and 10 are best Standard English.
-
1, 5 and 10 are best Standard English.
-
Acronym - .--
-
S = C + rC factor out C on the right side: S = C(1 + r) divide both sides by (1 + r): S/(1 + r) = C - .--
-
(fg)(x) = (-6x - 1)(4x^2) = -24x^3 - 4x^2 - .--
-
320/100 = x/200 The easiest way to isolate x is by cross multiplying. multiply the numerator of one side by the denominator of the other side: 320x = 100(200) 320x = 20,000 divide both sides by 320: x = 20,000/320 = 62.5 - .--
-
320/100 = x/200 The easiest way to isolate x is by cross multiplying. multiply the numerator of one side by the denominator of the other side: 320x = 100(200) 320x = 20,000 divide both sides by 320: x = 20,000/320 = 62.5 - .--
-
2.5(s - w) = 800 2(s + w) = 800 or s = 400 - w substitute second equation into first equation: 2.5(400 - w) - 2.5w = 800 1000 - 2.5w - 2.5w = 800 -5w = -200 w = -200/-5 = 40mi/hr using second equation: s = 400 - 40 = 360mi/hr check using …
-
2.5(s - w) = 800 2(s + w) = 800 or s = 400 - w substitute second equation into first equation: 2.5(400 - w) - 2.5w = 800 1000 - 2.5w - 2.5w = 800 -5w = -200 w = -200/-5 = 40mi/hr using second equation: s = 400 - 40 = 360mi/hr check using …
-
A = (20,000/35,000)(220,000) = Rs125,714.29 B = 220,000 - 125,714.29 = Rs 94,285.71 a ratio of 20/35 = 4/7 - .--
-
A = P(1 + r/n)^nt A = 20,000(1 + 0.05/365.25)^(365.25)(25) = 20,000(1.000137)^9131.25 = $69.869.40
-
A = p(1 + r/n)^nt 1,000,000 = 25,000(1 + 0.04/4)^4t 40 = (1.01)^4t ln40 = 4tln1.01 3.689 = 4(0.00995)t 3.689 = 0.0398t t = 3.689/0.0398 = 92.7 years check: 40 = (1.01)^4(92.7) 40 = 40 checks
-
A = P(1 + r/n)^nt A = 20,000(1 + 0.05/365.25)^(365.25)(25) = 20,000(1.000137)^9131.25 = $69.869.40
-
A = p(1 + r/n)^nt 1,000,000 = 25,000(1 + 0.04/4)^4t 40 = (1.01)^4t ln40 = 4tln1.01 3.689 = 4(0.00995)t 3.689 = 0.0398t t = 3.689/0.0398 = 92.7 years check: 40 = (1.01)^4(92.7) 40 = 40 checks
-
A = P(1 + r/n)^nt A = 20,000(1 + 0.05/365.25)^(365.25)(25) = 20,000(1.000137)^9131.25 = $69.869.40
-
A = p(1 + r/n)^nt 1,000,000 = 25,000(1 + 0.04/4)^4t 40 = (1.01)^4t ln40 = 4tln1.01 3.689 = 4(0.00995)t 3.689 = 0.0398t t = 3.689/0.0398 = 92.7 years check: 40 = (1.01)^4(92.7) 40 = 40 checks
-
A = (20,000/35,000)(220,000) = Rs125,714.29 B = 220,000 - 125,714.29 = Rs 94,285.71 a ratio of 20/35 = 4/7 - .--
-
2.5(s - w) = 800 2(s + w) = 800 or s = 400 - w substitute second equation into first equation: 2.5(400 - w) - 2.5w = 800 1000 - 2.5w - 2.5w = 800 -5w = -200 w = -200/-5 = 40mi/hr using second equation: s = 400 - 40 = 360mi/hr check using …
-
320/100 = x/200 The easiest way to isolate x is by cross multiplying. multiply the numerator of one side by the denominator of the other side: 320x = 100(200) 320x = 20,000 divide both sides by 320: x = 20,000/320 = 62.5 - .--
-
320/100 = x/200 The easiest way to isolate x is by cross multiplying. multiply the numerator of one side by the denominator of the other side: 320x = 100(200) 320x = 20,000 divide both sides by 320: x = 20,000/320 = 62.5 - .--
-
320/100 = x/200 The easiest way to isolate x is by cross multiplying. multiply the numerator of one side by the denominator of the other side: 320x = 100(200) 320x = 20,000 divide both sides by 320: x = 20,000/320 = 62.5 - .--
-
(fg)(x) = (-6x - 1)(4x^2) = -24x^3 - 4x^2 - .--
-
(fg)(x) = (-6x - 1)(4x^2) = -24x^3 - 4x^2 - .--
-
(fg)(x) = (-6x - 1)(4x^2) = -24x^3 - 4x^2 - .--