solve algebra problem!!!!!!?

This is the problem. Solve for C

S = C + rC

Thank you!

Comments

  • First , you want divide both sides by 'r'.

    Then you have S = C + C.

    That's the same as 2 * C or 2C.

    This you means you can divide both sides by 2.

    So it's S/2.

  • S = C + rC

    factor out C on the right side:

    S = C(1 + r)

    divide both sides by (1 + r):

    S/(1 + r) = C

    - .--

  • S = C + rC

    S = C ( 1 + r)

    C = S / ( 1 + r) ANSWER

  • S = C + rC

    S = 1C + rC

    S = (1+r)C

    S/(1+r) = C

  • 1. Factor out the C on the right: s = C (1 + r)

    2. Divide both sides by (1+r): s/(r+1) = c

  • B/2 = -7 + B multiply the two aspects by 2 (*2)B/2 = 2(-7+B) simplify B = -14 + 2B subtract 2B from the two aspects B (-2B) = -14 + 2B (-2B) simplify -B = -14 divide by a unfavourable to isolate your variable -B/- = -14/- simplify B = 14 --------------------------------------... to examine: positioned your fee for B that's 14 interior the equation the place B is located 14/2 = -7+14 7 = 7 and the solutions are an analogous so that's right

  • S=r since you woud subtract c from one side then divide c by c and be left with S = r (i think)

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