wile-e
wile-e
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Rate-of-change denotes a derivative, or slope. 2.2 ≤ x ≤ 6.1 defines the domain of a straight line segment and the slope of a straight line is zero, so Average Rate = 0 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
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y² - 2x + 3y - 7 = 0 - 2x = - y² - 3y + 7 2x = y² - 3y - 7 x = 1/2 y² - 3/2 x - 7/2 y-int.: x = 0: 1/2 y² - 3/2 y - 7/2 = 0 2(1/2 y²) - 2(3/2 y) - 2(7/2) = 2(0) y² - 3y - 7 = 0 y² - 3y = 7 y² - 3y + 2.25 = 7 + 2.25 (y - 1.5)² = 9.25 y…
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Diameter = 4 cm. Depth = 1 cm. The diameter of the parabola defines a point P(x, y) as: P(4, 0): x = 4 y = 0 Half the diameter defines the x-value of the vertex, h, as h = 1/2 x h = 1/2 (4) h = 2 The depth, k, defines the y-v…
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No. Dozen Roses = r No. Dozen Carnations = c r + c = 17 c = 17 - r ............... Eq. 1 15r + 8c = 192 .... Eq. 2 Sub 17 - r from Eq. 1 for c in Eq. 2: 15r + 8(17 - r) = 192 15r + 136 - 8r = 192 7r = 192 - 136 7r = 56 r = 56 / 7…
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Speed of One Train, R1 = 72 km./hr. Speed of Other Train, R2 = 68 km./hr. Distance, D = 560 km. Since the two trains are moving away from each other, Overall Speed, Rt = R1 + R2 Rt= 72 + 68 Rt = 140 km./hr. D = (Rt)t 560 = 140t t = 56…
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Ms. Chan's Age = x Son's Age = y x + y = 35....................Eq. 1 x = y + 34....................Eq. 2 Sub y + 35 from Eq. 2 for x in Eq. 1: y + 34 + y = 35 2y + 34 = 35 2y = 35 - 34 2y = 1 y = 1/2 Ms. Chan's son is 6 mos. old.…
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h(x) = 0.7x + 40 x = 57 h(57) = 0.7(57) + 40 h(57) = 39.9 + 40 h(57) = 79.9 The waiter would make $79.90 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
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h(x) = 0.7x + 40 x = 57 h(57) = 0.7(57) + 40 h(57) = 39.9 + 40 h(57) = 79.9 The waiter would make $79.90 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
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Ms. Chan's Age = x Son's Age = y x + y = 35....................Eq. 1 x = y + 34....................Eq. 2 Sub y + 35 from Eq. 2 for x in Eq. 1: y + 34 + y = 35 2y + 34 = 35 2y = 35 - 34 2y = 1 y = 1/2 Ms. Chan's son is 6 mos. old.…
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Speed of One Train, R1 = 72 km./hr. Speed of Other Train, R2 = 68 km./hr. Distance, D = 560 km. Since the two trains are moving away from each other, Overall Speed, Rt = R1 + R2 Rt= 72 + 68 Rt = 140 km./hr. D = (Rt)t 560 = 140t t = 56…
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Speed of One Train, R1 = 72 km./hr. Speed of Other Train, R2 = 68 km./hr. Distance, D = 560 km. Since the two trains are moving away from each other, Overall Speed, Rt = R1 + R2 Rt= 72 + 68 Rt = 140 km./hr. D = (Rt)t 560 = 140t t = 56…
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No. Dozen Roses = r No. Dozen Carnations = c r + c = 17 c = 17 - r ............... Eq. 1 15r + 8c = 192 .... Eq. 2 Sub 17 - r from Eq. 1 for c in Eq. 2: 15r + 8(17 - r) = 192 15r + 136 - 8r = 192 7r = 192 - 136 7r = 56 r = 56 / 7…
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Diameter = 4 cm. Depth = 1 cm. The diameter of the parabola defines a point P(x, y) as: P(4, 0): x = 4 y = 0 Half the diameter defines the x-value of the vertex, h, as h = 1/2 x h = 1/2 (4) h = 2 The depth, k, defines the y-v…
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y² - 2x + 3y - 7 = 0 - 2x = - y² - 3y + 7 2x = y² - 3y - 7 x = 1/2 y² - 3/2 x - 7/2 y-int.: x = 0: 1/2 y² - 3/2 y - 7/2 = 0 2(1/2 y²) - 2(3/2 y) - 2(7/2) = 2(0) y² - 3y - 7 = 0 y² - 3y = 7 y² - 3y + 2.25 = 7 + 2.25 (y - 1.5)² = 9.25 y…
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Rate-of-change denotes a derivative, or slope. 2.2 ≤ x ≤ 6.1 defines the domain of a straight line segment and the slope of a straight line is zero, so Average Rate = 0 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯