wayne-deguman
wayne-deguman
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Question papers and mark schemes older than 9 months are published. i.e. June 2013 have only just been produced. Here's a link: http://www.edexcel.com/i-am-a/student/Pages/pastpa... :)>
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x³ - 4x = x(x² - 4) = x(x - 2)(x + 2) x² + 3x + 2 = (x + 1)(x + 2) => x(x - 2)(x + 2)/(x + 1)(x + 2) i.e. x(x - 2)/(x + 1) :)>
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x³ - 4x = x(x² - 4) = x(x - 2)(x + 2) x² + 3x + 2 = (x + 1)(x + 2) => x(x - 2)(x + 2)/(x + 1)(x + 2) i.e. x(x - 2)/(x + 1) :)>
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1) √(2x - 1) = x - 8 => 2x - 1 = (x - 8)² => 2x - 1 = x² - 16x + 64 i.e. x² - 18x + 65 = 0 => (x - 13)(x - 5) = 0 so, x = 13 or x = 5 2) 8i/(2 + i) x (2 - i)/(2 - i) => 8i(2 - i)/(4 - i²) => (16i - 8i²)/(4 - i²…
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1) √(2x - 1) = x - 8 => 2x - 1 = (x - 8)² => 2x - 1 = x² - 16x + 64 i.e. x² - 18x + 65 = 0 => (x - 13)(x - 5) = 0 so, x = 13 or x = 5 2) 8i/(2 + i) x (2 - i)/(2 - i) => 8i(2 - i)/(4 - i²) => (16i - 8i²)/(4 - i²…
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10 centimetres is 1/10 of a metre => 399.95 ≤ d < 400.05 (metres) => 59.95 ≤ t < 60.05 (seconds) Speed is d/t, so upper bound is 400.05/59.95 = 6.6731 m/s => lower bound is 399.95/60.05 = 6.6603 m/s So, in km/h --> u…
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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You are correct. Is the 'correct' answer a printed one in a book? :)>
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You are correct. Is the 'correct' answer a printed one in a book? :)>
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You are correct. Is the 'correct' answer a printed one in a book? :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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|3x 2|.|2..4| = |-10 16| |3..0|..|1 -y|....|6...12| so, 6x + 2 = -10 => x = -2 And, 12x - 2y = 16 => -24 - 2y = 16 i.e. y = -20 :)>
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10 centimetres is 1/10 of a metre => 399.95 ≤ d < 400.05 (metres) => 59.95 ≤ t < 60.05 (seconds) Speed is d/t, so upper bound is 400.05/59.95 = 6.6731 m/s => lower bound is 399.95/60.05 = 6.6603 m/s So, in km/h --> u…
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10 centimetres is 1/10 of a metre => 399.95 ≤ d < 400.05 (metres) => 59.95 ≤ t < 60.05 (seconds) Speed is d/t, so upper bound is 400.05/59.95 = 6.6731 m/s => lower bound is 399.95/60.05 = 6.6603 m/s So, in km/h --> u…
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10 centimetres is 1/10 of a metre => 399.95 ≤ d < 400.05 (metres) => 59.95 ≤ t < 60.05 (seconds) Speed is d/t, so upper bound is 400.05/59.95 = 6.6731 m/s => lower bound is 399.95/60.05 = 6.6603 m/s So, in km/h --> u…
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1) √(2x - 1) = x - 8 => 2x - 1 = (x - 8)² => 2x - 1 = x² - 16x + 64 i.e. x² - 18x + 65 = 0 => (x - 13)(x - 5) = 0 so, x = 13 or x = 5 2) 8i/(2 + i) x (2 - i)/(2 - i) => 8i(2 - i)/(4 - i²) => (16i - 8i²)/(4 - i²…
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Question papers and mark schemes older than 9 months are published. i.e. June 2013 have only just been produced. Here's a link: http://www.edexcel.com/i-am-a/student/Pages/pastpa... :)>