rapidfire
rapidfire
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Division always comes before addition unless there are brackets. Integration by substitution is not required for this integral. â« (eË / 1 + eË) dx â« (eË + eË) dx â« 2eË dx 2 â« eË dx 2eË + C
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Division always comes before addition unless there are brackets. Integration by substitution is not required for this integral. â« (eË / 1 + eË) dx â« (eË + eË) dx â« 2eË dx 2 â« eË dx 2eË + C
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Well done, you have simplified the expression as far as possible.
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Integration by substitution is not required because it is only a linear function within the beacket. Simply integrate as normal then divide by the derivative of the bracket. ∫ e ^ (2 - x) dx e ^ (2 - x) / -1 + C -e ^ (2 - x) + C
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There is no need for brackets around single terms as you have here. Find the general solution by separating the variables then integrating: 6y(dy / dx) = 7x² - 3x + 9 y dy = (7x² / 6 - x / 2 + 3 / 2) dx ∫ y dy = ∫ (7x² / 6 - x / 2 + 3 / 2) dx …
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There is no need for brackets around single terms as you have here. Find the general solution by separating the variables then integrating: 6y(dy / dx) = 7x² - 3x + 9 y dy = (7x² / 6 - x / 2 + 3 / 2) dx ∫ y dy = ∫ (7x² / 6 - x / 2 + 3 / 2) dx …
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There is no need for brackets around single terms as you have here. Find the general solution by separating the variables then integrating: 6y(dy / dx) = 7x² - 3x + 9 y dy = (7x² / 6 - x / 2 + 3 / 2) dx ∫ y dy = ∫ (7x² / 6 - x / 2 + 3 / 2) dx …
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Integration by substitution is not required because it is only a linear function within the beacket. Simply integrate as normal then divide by the derivative of the bracket. ∫ e ^ (2 - x) dx e ^ (2 - x) / -1 + C -e ^ (2 - x) + C
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Well done, you have simplified the expression as far as possible.
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Well done, you have simplified the expression as far as possible.