Simplify e^(2 ln x + cos x)?

jsjs
in Science & Mathematics

This is what I get:

[e^(2 ln x)] * [e^(cos x)]

[e^(ln x^2)] * [e^(cos x)]

[x^2] * [e^(cos x)]

If I'm on the right track, then I don't know how to simplify e^(cos x)

Comments

  • rapidfirerapidfire

    Well done, you have simplified the expression as far as possible.

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