Default Avatar

philo

philo

About

Username
philo
Joined
Visits
0
Last Active
Roles
Member

Comments

  • if m is divisible by 3, m = 3n for some integer n. then 3n = 121 - 5k n = 40 1/3 - 5/3 k 40 1/3 - 5/3 (0) = 40 1/3 40 1/3 - 5/3 (1) = 38 2/3 40 1/3 - 5/3 (2) = 37 and 40 1/3 - 5/3 (5) = 32 when k = 2 mod 3, m = 0 mod 3, but m can be eit…
    in math problem? Comment by philo June 2021
  • if m is divisible by 3, m = 3n for some integer n. then 3n = 121 - 5k n = 40 1/3 - 5/3 k 40 1/3 - 5/3 (0) = 40 1/3 40 1/3 - 5/3 (1) = 38 2/3 40 1/3 - 5/3 (2) = 37 and 40 1/3 - 5/3 (5) = 32 when k = 2 mod 3, m = 0 mod 3, but m can be eit…
    in math problem? Comment by philo June 2021
  • rational root theorem suggests trying ±1, ±2, and so on (factors of 12) as roots. synthetic division with x = 1 gives us (x - 1)(x² + x - 12) = (x - 1)(x + 4)(x - 3)
  • rational root theorem suggests trying ±1, ±2, and so on (factors of 12) as roots. synthetic division with x = 1 gives us (x - 1)(x² + x - 12) = (x - 1)(x + 4)(x - 3)
  • that's x+4 and 5x+2? your plus signs don't show. (x+4) / (x-2) = r = (5x+2)/(x+4) (x+4)² = (x-2)(5x+2) x² + 8x + 16 = 5x² - 8x - 4 0 = 4x² - 16x - 20 x² - 4x - 5 = 0 (x - 5)(x + 1) = 0 x = 5 or x = -1 so r = (5+4)/(5-2) = 3 = (25+2)/(5+4)…
  • that's x+4 and 5x+2? your plus signs don't show. (x+4) / (x-2) = r = (5x+2)/(x+4) (x+4)² = (x-2)(5x+2) x² + 8x + 16 = 5x² - 8x - 4 0 = 4x² - 16x - 20 x² - 4x - 5 = 0 (x - 5)(x + 1) = 0 x = 5 or x = -1 so r = (5+4)/(5-2) = 3 = (25+2)/(5+4)…
  • If the interest rate is 5%, you multiply by 1.05 to do the compounding (think about it). The 1 is all of the amount and the .05 is the interest on the amount, so when you add the interest to the original, you get (1 + interest rate) TIMES the origi…
  • If the interest rate is 5%, you multiply by 1.05 to do the compounding (think about it). The 1 is all of the amount and the .05 is the interest on the amount, so when you add the interest to the original, you get (1 + interest rate) TIMES the origi…
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½
  • -2w² + 5w = 0 w(-2w + 5) = 0 w = 0 or -2w + 5 = 0 → 2w = 5 → w = 2½