question type a million For this polynomial equation x^2 -14*x -fifty one = 0, answer right here questions : A. resolve by using Factorization answer For question a million x^2 -14*x -fifty one = 0 And we get P(x)=x^2 -14*x -fifty one Now, we are able to seek for the roots of P(x) utilising fairly some set of rules : 1A. resolve by using Factorization x^2 -14*x -fifty one = 0 Separate : ( x^2 +3*x ) + ( -17*x -fifty one ) = 0 Commutative regulation : ( x^2 -17*x ) + ( 3*x -fifty one ) = 0 Distributive regulation : x*( x -17 ) + 3*( x -17 ) = 0 ingredient : ( x +3 )*( x -17 ) So the Polynomial have 2 roots : x1 = -3 x2 = 17
Comments
Start by taking our the common factor, which is w.
w (-2w + 5) = 0
Solve both factor for w, by setting each equal to zero, since at least one of the factors must equal zero for the whole thing to equal zero.
w = 0 and
-2w +5 = 0
-2w = -5
w = 5/2 or 2.5
Your solutions then are w = 0 and w = 2.5
-2w^2 + 5w = 0
Factor out a w.
w( -2w + 5 ) = 0
Set each side to zero ( since X * Y = 0, X or Y must be 0).
w = 0 or -2w + 5 = 0 -> -2w = -5 -> w = 5/2 ( w = 2.5 )
Answer: w = 0, 2.5
-2w² + 5w = 0
w(-2w + 5) = 0
w = 0 or
-2w + 5 = 0 → 2w = 5 → w = 2½
question type a million For this polynomial equation x^2 -14*x -fifty one = 0, answer right here questions : A. resolve by using Factorization answer For question a million x^2 -14*x -fifty one = 0 And we get P(x)=x^2 -14*x -fifty one Now, we are able to seek for the roots of P(x) utilising fairly some set of rules : 1A. resolve by using Factorization x^2 -14*x -fifty one = 0 Separate : ( x^2 +3*x ) + ( -17*x -fifty one ) = 0 Commutative regulation : ( x^2 -17*x ) + ( 3*x -fifty one ) = 0 Distributive regulation : x*( x -17 ) + 3*( x -17 ) = 0 ingredient : ( x +3 )*( x -17 ) So the Polynomial have 2 roots : x1 = -3 x2 = 17
-w(2w-5)=0
w=0
w=5/2