notthejake
notthejake
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suppose they bought all 30 $21 tickets -- that would be $630. but they spent an additional $66 each $27 ticket costs $6 more , so this is 11 $27 tickets (trade 11 $21 tickets for 11 $27 tickets adds an additional $66, making the total 630 + 66 …
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Your formula for #1 looks right: t = 1 / c [ln A - ln (A - N)] = 1 / c ln [A / (A - N)] = ln [A / (A - N)]^(1/c) so far so good... when I plug in A = 65, N = 30, and c = .03: t = ln [65 / 35]^(1/.03) = ln [1.857^33.33] = 20.63 weeks di…
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Your formula for #1 looks right: t = 1 / c [ln A - ln (A - N)] = 1 / c ln [A / (A - N)] = ln [A / (A - N)]^(1/c) so far so good... when I plug in A = 65, N = 30, and c = .03: t = ln [65 / 35]^(1/.03) = ln [1.857^33.33] = 20.63 weeks di…
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I believe it could either be 8 or 9 suppose that the min inclination is due east, at 7 degrees then the mam inclination would be due west, at 9 degrees if the "center of oscillation", or "middle" inclination is due east, t…
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4) the sum of kim's age k and twice sue's age s is 52 ==> k + 2s = 52 sue's age subtracted from twice kim's age is 29 ==> 2k - s = 29 k + 2s = 52 4k - 2s = 58 (twice the second equation) ------------------ (add) 5k = 110 ==> k = 110…
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4) the sum of kim's age k and twice sue's age s is 52 ==> k + 2s = 52 sue's age subtracted from twice kim's age is 29 ==> 2k - s = 29 k + 2s = 52 4k - 2s = 58 (twice the second equation) ------------------ (add) 5k = 110 ==> k = 110…
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69.70 - 39.95 = 29.75 = usage cost 29.75 / .35 = 2975 / 35 = 85 85 additional minutes beyond the 500 free minutes 85 * .35 = 29.75 +39.95 = 69.70 total bill
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69.70 - 39.95 = 29.75 = usage cost 29.75 / .35 = 2975 / 35 = 85 85 additional minutes beyond the 500 free minutes 85 * .35 = 29.75 +39.95 = 69.70 total bill
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69.70 - 39.95 = 29.75 = usage cost 29.75 / .35 = 2975 / 35 = 85 85 additional minutes beyond the 500 free minutes 85 * .35 = 29.75 +39.95 = 69.70 total bill
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69.70 - 39.95 = 29.75 = usage cost 29.75 / .35 = 2975 / 35 = 85 85 additional minutes beyond the 500 free minutes 85 * .35 = 29.75 +39.95 = 69.70 total bill
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69.70 - 39.95 = 29.75 = usage cost 29.75 / .35 = 2975 / 35 = 85 85 additional minutes beyond the 500 free minutes 85 * .35 = 29.75 +39.95 = 69.70 total bill
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69.70 - 39.95 = 29.75 = usage cost 29.75 / .35 = 2975 / 35 = 85 85 additional minutes beyond the 500 free minutes 85 * .35 = 29.75 +39.95 = 69.70 total bill
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4) the sum of kim's age k and twice sue's age s is 52 ==> k + 2s = 52 sue's age subtracted from twice kim's age is 29 ==> 2k - s = 29 k + 2s = 52 4k - 2s = 58 (twice the second equation) ------------------ (add) 5k = 110 ==> k = 110…
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4) the sum of kim's age k and twice sue's age s is 52 ==> k + 2s = 52 sue's age subtracted from twice kim's age is 29 ==> 2k - s = 29 k + 2s = 52 4k - 2s = 58 (twice the second equation) ------------------ (add) 5k = 110 ==> k = 110…
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4) the sum of kim's age k and twice sue's age s is 52 ==> k + 2s = 52 sue's age subtracted from twice kim's age is 29 ==> 2k - s = 29 k + 2s = 52 4k - 2s = 58 (twice the second equation) ------------------ (add) 5k = 110 ==> k = 110…
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4) the sum of kim's age k and twice sue's age s is 52 ==> k + 2s = 52 sue's age subtracted from twice kim's age is 29 ==> 2k - s = 29 k + 2s = 52 4k - 2s = 58 (twice the second equation) ------------------ (add) 5k = 110 ==> k = 110…
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4) the sum of kim's age k and twice sue's age s is 52 ==> k + 2s = 52 sue's age subtracted from twice kim's age is 29 ==> 2k - s = 29 k + 2s = 52 4k - 2s = 58 (twice the second equation) ------------------ (add) 5k = 110 ==> k = 110…
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I believe it could either be 8 or 9 suppose that the min inclination is due east, at 7 degrees then the mam inclination would be due west, at 9 degrees if the "center of oscillation", or "middle" inclination is due east, t…
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I believe it could either be 8 or 9 suppose that the min inclination is due east, at 7 degrees then the mam inclination would be due west, at 9 degrees if the "center of oscillation", or "middle" inclination is due east, t…
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I believe it could either be 8 or 9 suppose that the min inclination is due east, at 7 degrees then the mam inclination would be due west, at 9 degrees if the "center of oscillation", or "middle" inclination is due east, t…
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I believe it could either be 8 or 9 suppose that the min inclination is due east, at 7 degrees then the mam inclination would be due west, at 9 degrees if the "center of oscillation", or "middle" inclination is due east, t…
-
Your formula for #1 looks right: t = 1 / c [ln A - ln (A - N)] = 1 / c ln [A / (A - N)] = ln [A / (A - N)]^(1/c) so far so good... when I plug in A = 65, N = 30, and c = .03: t = ln [65 / 35]^(1/.03) = ln [1.857^33.33] = 20.63 weeks di…
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Your formula for #1 looks right: t = 1 / c [ln A - ln (A - N)] = 1 / c ln [A / (A - N)] = ln [A / (A - N)]^(1/c) so far so good... when I plug in A = 65, N = 30, and c = .03: t = ln [65 / 35]^(1/.03) = ln [1.857^33.33] = 20.63 weeks di…
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suppose they bought all 30 $21 tickets -- that would be $630. but they spent an additional $66 each $27 ticket costs $6 more , so this is 11 $27 tickets (trade 11 $21 tickets for 11 $27 tickets adds an additional $66, making the total 630 + 66 …