nancydrew
nancydrew
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You can see that x-3 works if you set the the polynomial equal to zero and let x=3. Then you can divide x^3-27 by x-3 to get the remaining polynomial which is x^2+3x+9, which is unfactorable unless you want to work with complex numbers. So (x-3)(x^2…
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You can see that x-3 works if you set the the polynomial equal to zero and let x=3. Then you can divide x^3-27 by x-3 to get the remaining polynomial which is x^2+3x+9, which is unfactorable unless you want to work with complex numbers. So (x-3)(x^2…
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You can see that x-3 works if you set the the polynomial equal to zero and let x=3. Then you can divide x^3-27 by x-3 to get the remaining polynomial which is x^2+3x+9, which is unfactorable unless you want to work with complex numbers. So (x-3)(x^2…