How do you factor X^3 - 27??

I TOTALLY FORGOT HOW TO

Comments

  • (X-3)(x^2+3x+9)

  • You can see that x-3 works if you set the the polynomial equal to zero and let x=3. Then you can divide x^3-27 by x-3 to get the remaining polynomial which is x^2+3x+9, which is unfactorable unless you want to work with complex numbers. So (x-3)(x^2+3x+9).

  • Since x=3 is a solution, (x-3) is a factor. I would use synthetic division to figure out the rest: (x-3)(x^2+3x+9).

  • One roor is 3 so you should find the other factor dividing by

    (x-3)

    x^3-27 = (x-3)*(x^2+3x+9)

  • (x-3)(x-3)(x-3)

  • use difference of cubes.

    Easy as Pi.

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