Comments

• Q = 100*(1 - 0.18)^24 = 0.854 g ---------------

  in How do you do THIS algebra 2 problem? Comment by m3 June 2021
• pues dile a tu mamá que es lo que esta pasando, a nadie le gusta estar donde te tratan feo.

  in ¿Como hago para que me entienda? Comment by m3 June 2021
• reqd. probability = P[A not working & circuit D-E-F working] / P[system working] = 0.3*(0.8)^3 / 0.75112 = 0.2045

  in probability? system of components? Comment by m3 June 2021
• P[diseased & heavy drinker] = 7.1% *6% = 4.26% P[healthy & heavy drinker ] = 12% * 92.1% = 11.052% P[diseased | heavy drinker ] = 4.26/(4.26+11.052) = .2782 <-----

  in empirical probability problem? Comment by m3 May 2021
• this is a committee, it is the constitution of the committee that matters, not the order in which the members are chosen, so it is a combination problem 100c5 = 100!/(5!*95!) = 75287520 <----------

  in Algebra 2 word problem, please help? Comment by m3 May 2021
• this is a committee, it is the constitution of the committee that matters, not the order in which the members are chosen, so it is a combination problem 100c5 = 100!/(5!*95!) = 75287520 <----------

  in Algebra 2 word problem, please help? Comment by m3 May 2021
• since yearly rate of appreciatio has been asked for, we use blocks of 1 year A = P(1+ r)^n plugging in, 191,000 = 120,000(1+r)^10 (1+r)^10 = (191/120) (1+r) = (191/120)^(1/10) = 1.04758 r = 0.04758 = 4.76% to 2 dp ------------------------

  in Algebra 2- Word problem. Please help.? Comment by m3 May 2021
• since yearly rate of appreciatio has been asked for, we use blocks of 1 year A = P(1+ r)^n plugging in, 191,000 = 120,000(1+r)^10 (1+r)^10 = (191/120) (1+r) = (191/120)^(1/10) = 1.04758 r = 0.04758 = 4.76% to 2 dp ------------------------

  in Algebra 2- Word problem. Please help.? Comment by m3 May 2021
• this is a committee, it is the constitution of the committee that matters, not the order in which the members are chosen, so it is a combination problem 100c5 = 100!/(5!*95!) = 75287520 <----------

  in Algebra 2 word problem, please help? Comment by m3 May 2021
• P[diseased & heavy drinker] = 7.1% *6% = 4.26% P[healthy & heavy drinker ] = 12% * 92.1% = 11.052% P[diseased | heavy drinker ] = 4.26/(4.26+11.052) = .2782 <-----

  in empirical probability problem? Comment by m3 May 2021
• P[diseased & heavy drinker] = 7.1% *6% = 4.26% P[healthy & heavy drinker ] = 12% * 92.1% = 11.052% P[diseased | heavy drinker ] = 4.26/(4.26+11.052) = .2782 <-----

  in empirical probability problem? Comment by m3 May 2021
• P[diseased & heavy drinker] = 7.1% *6% = 4.26% P[healthy & heavy drinker ] = 12% * 92.1% = 11.052% P[diseased | heavy drinker ] = 4.26/(4.26+11.052) = .2782 <-----

  in empirical probability problem? Comment by m3 May 2021
• P[diseased & heavy drinker] = 7.1% *6% = 4.26% P[healthy & heavy drinker ] = 12% * 92.1% = 11.052% P[diseased | heavy drinker ] = 4.26/(4.26+11.052) = .2782 <-----

  in empirical probability problem? Comment by m3 May 2021
• pues dile a tu mamá que es lo que esta pasando, a nadie le gusta estar donde te tratan feo.

  in ¿Como hago para que me entienda? Comment by m3 May 2021
• Q = 100*(1 - 0.18)^24 = 0.854 g ---------------

  in How do you do THIS algebra 2 problem? Comment by m3 May 2021