ireadlots
ireadlots
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If the first digit of the original number is a, the second b and the third c, then the original number is 100a + 10b + c The reversed number is 100c + 10b + a 100a + 10b + c + 396 = 100c + 10b + a 99a -99c + 396 =0 99(c-a) = 396 c-a = 396/…
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If the first digit of the original number is a, the second b and the third c, then the original number is 100a + 10b + c The reversed number is 100c + 10b + a 100a + 10b + c + 396 = 100c + 10b + a 99a -99c + 396 =0 99(c-a) = 396 c-a = 396/…
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I'm assuming you can handle long division and multiplication, without me writing it out, but I've avoided it where possible, by using factoring... Start with the squared part: 59^(2/3) = (59^2)^1/3 ((60-1)^2)^(1/3) = (60^2 - 2*60*1^2) =(3600 - …
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I'm assuming you can handle long division and multiplication, without me writing it out, but I've avoided it where possible, by using factoring... Start with the squared part: 59^(2/3) = (59^2)^1/3 ((60-1)^2)^(1/3) = (60^2 - 2*60*1^2) =(3600 - …
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You have a line passing through (1,4) and (3,8) and you need to find a line parallel to it that passes through (5,3). Things you need to know: 1) The slope of a line between two points is given by the formula slope = rise/run or m = (y2-y1)/(x…
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You have a line passing through (1,4) and (3,8) and you need to find a line parallel to it that passes through (5,3). Things you need to know: 1) The slope of a line between two points is given by the formula slope = rise/run or m = (y2-y1)/(x…
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If the first digit of the original number is a, the second b and the third c, then the original number is 100a + 10b + c The reversed number is 100c + 10b + a 100a + 10b + c + 396 = 100c + 10b + a 99a -99c + 396 =0 99(c-a) = 396 c-a = 396/…