algebra?????????????????

Comments

• ireadlots

  June 2021

  You have a line passing through (1,4) and (3,8) and you need to find a line parallel to it that passes through (5,3).

  Things you need to know:

  1) The slope of a line between two points is given by the formula slope = rise/run or

  m = (y2-y1)/(x2-x1)

  2) If 2 lines are parallel, they have the same slope

  3) If a line equation is in the form y = mx+b, m is the slope, and b is the y intercept.

  Now, we use this information to solve your problem:

  Step 1 - Find the slope of the line

  m = (8-4)/(3-1) = 4/2 = 2

  Step 3 - Find the equation of a line with slope 2 that passes through (5,3)

  y = mx + b

  3 = 2*(5) + b

  Solve for b

  3 = 15 + b

  b = 3-15 = -12

  So, your line is y = 2x-12

  solve the following system of equations

  X +Y=7 -> equation 1

  2X-3y=-6 -> equation 2

  You can do this 2 ways - substitution or elimination - your choice, whichever you think is easier.

  1) Substitution

  Start by rearranging the first equation to get one value in terms of the other:

  x = 7-y

  Now plug 7-y into the second equation where is says x

  2x - 3y = -6

  2(7-y) - 3y = -6

  14 - 2y-3y = -6

  14-5y = -6

  -5y = -20

  y = 4

  Now x = 7-y = 7-4 = 3

  2) Elimination

  Start by multiplying every term in the first equation by 2

  x+y = 7

  2x + 2y = 14

  Now subtract the second equation from the first

  2x + 2y = 14 -

  2x - 3y = -6

  -----------------

  2x - 2x + 2y - (-3y) = 14 - (-6)

  2y+3y = 14+6

  5y = 20

  y = 4

  Now solve the first equation for x

  x+y = 7

  x + 4 = 7

  x = 3