grunfeld
grunfeld
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a - w = 320 a + w = 400 2a = 720 a = 360 mph w = 40 mph
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a - w = 320 a + w = 400 2a = 720 a = 360 mph w = 40 mph
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I'm working on it. Here's what I have so far. The first exponent is 1 / 2. each subsequent exponent increases by geometric series. t_2 = 2^( 1 / 2 + 1 / 4 ) t_3 = 2^( 1 / 2 + 1 / 4 + 1 / 8 ) I solved it. t_n = 2^[ sigma( from 1 to n ) { (…
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I'm working on it. Here's what I have so far. The first exponent is 1 / 2. each subsequent exponent increases by geometric series. t_2 = 2^( 1 / 2 + 1 / 4 ) t_3 = 2^( 1 / 2 + 1 / 4 + 1 / 8 ) I solved it. t_n = 2^[ sigma( from 1 to n ) { (…
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If you want an accurate answer to this, you can use Newton's method. Rewrite it as below: y^3 - 1004 = 0 all you want is the root of the equation.
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u = ( 1 / 5 )x y = ( 1 / 3)u z = 3 ( u - y ) z = 2u x = 5u u + y + z = u 5u + 2u + u = u
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u = ( 1 / 5 )x y = ( 1 / 3)u z = 3 ( u - y ) z = 2u x = 5u u + y + z = u 5u + 2u + u = u
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all these can be done with the following formulas: y - y1 = m(x - x1) and m = (y2 - y1) / (x2 - x1) y - 5 = (-1 / 7)(x - 4) y - 5 = ( - 1 / 7)x + 4 / 7 y = ( -1 / 7)x + (39 / 7)
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all these can be done with the following formulas: y - y1 = m(x - x1) and m = (y2 - y1) / (x2 - x1) y - 5 = (-1 / 7)(x - 4) y - 5 = ( - 1 / 7)x + 4 / 7 y = ( -1 / 7)x + (39 / 7)
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Sarah = 150 Danielle = 15 Rebecca = 5
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9 / sin (theta ) = 22 / sin 31 9 sin 31 / 22 = sin ( theta )
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9 / sin (theta ) = 22 / sin 31 9 sin 31 / 22 = sin ( theta )
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Sarah = 150 Danielle = 15 Rebecca = 5
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all these can be done with the following formulas: y - y1 = m(x - x1) and m = (y2 - y1) / (x2 - x1) y - 5 = (-1 / 7)(x - 4) y - 5 = ( - 1 / 7)x + 4 / 7 y = ( -1 / 7)x + (39 / 7)
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u = ( 1 / 5 )x y = ( 1 / 3)u z = 3 ( u - y ) z = 2u x = 5u u + y + z = u 5u + 2u + u = u
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u = ( 1 / 5 )x y = ( 1 / 3)u z = 3 ( u - y ) z = 2u x = 5u u + y + z = u 5u + 2u + u = u
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If you want an accurate answer to this, you can use Newton's method. Rewrite it as below: y^3 - 1004 = 0 all you want is the root of the equation.
-
If you want an accurate answer to this, you can use Newton's method. Rewrite it as below: y^3 - 1004 = 0 all you want is the root of the equation.
-
I'm working on it. Here's what I have so far. The first exponent is 1 / 2. each subsequent exponent increases by geometric series. t_2 = 2^( 1 / 2 + 1 / 4 ) t_3 = 2^( 1 / 2 + 1 / 4 + 1 / 8 ) I solved it. t_n = 2^[ sigma( from 1 to n ) { (…
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I'm working on it. Here's what I have so far. The first exponent is 1 / 2. each subsequent exponent increases by geometric series. t_2 = 2^( 1 / 2 + 1 / 4 ) t_3 = 2^( 1 / 2 + 1 / 4 + 1 / 8 ) I solved it. t_n = 2^[ sigma( from 1 to n ) { (…
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I'm working on it. Here's what I have so far. The first exponent is 1 / 2. each subsequent exponent increases by geometric series. t_2 = 2^( 1 / 2 + 1 / 4 ) t_3 = 2^( 1 / 2 + 1 / 4 + 1 / 8 ) I solved it. t_n = 2^[ sigma( from 1 to n ) { (…
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a - w = 320 a + w = 400 2a = 720 a = 360 mph w = 40 mph