formula for a series?

:)

√ 2, √ (2√ 2), √ (2√(2√ 2))

cant come up with a formula

Comments

  • I'm working on it.

    Here's what I have so far.

    The first exponent is 1 / 2.

    each subsequent exponent increases by geometric series. t_2 = 2^( 1 / 2 + 1 / 4 )

    t_3 = 2^( 1 / 2 + 1 / 4 + 1 / 8 )

    I solved it. t_n = 2^[ sigma( from 1 to n ) { (1 / 2 )^n } ]

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