gile
gile
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cos2x - 4cosx - 5 = 0 2cos²x - 1 - 4cosx - 5 = 0 2cos²x - 4cosx - 6 = 0 cos²x - 2cosx - 3 = 0 (cosx + 1)(cosx - 3) = 0 cosx - 3 ≠ 0 Hence cosx + 1 = 0 cosx = -1 x = (2k + 1)π
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cos2x - 4cosx - 5 = 0 2cos²x - 1 - 4cosx - 5 = 0 2cos²x - 4cosx - 6 = 0 cos²x - 2cosx - 3 = 0 (cosx + 1)(cosx - 3) = 0 cosx - 3 ≠ 0 Hence cosx + 1 = 0 cosx = -1 x = (2k + 1)π
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F(x) is the value of the function when the variable receives the value x. When the variable increases by h, its new value is x + h, and your teacher asked you to evaluate the corresponding value of the function. If F(x) = 2x + 1, then F(x+h) =…
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Let's denote the magnitude of a vector V by |V| Given: |A + B| = n|A - B| Squaring both sides: |A + B|² = n²|A - B|² Since V² = |V|², (A + B)² = n²(A - B)² Performing the operation on vectors: A² + 2AB + B² = n²(A² - 2AB + B²) |A| = |B|==…
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5 + 5lnx = 20 5lnx = 15 lnx = 3 x = e³
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E = mc² Hence E can be measured in kg.m²/s² (= joule)
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E = mc² Hence E can be measured in kg.m²/s² (= joule)
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4ln(x) - 3ln(x + 1) + 2ln(x + 4) = ln(x⁴) - ln[(x + 1)³] + ln[(x + 4)²] = ln[x⁴(x + 4)²/(x + 1)³]
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(a) When you ride slowly through the traffic, the frequency of the vibration of your bike is far below the natural frequency of the bags, the forced oscillation on the bags is negligible. When you are speeding up to climb the slope, the frequency o…
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(a) When you ride slowly through the traffic, the frequency of the vibration of your bike is far below the natural frequency of the bags, the forced oscillation on the bags is negligible. When you are speeding up to climb the slope, the frequency o…
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(a) When you ride slowly through the traffic, the frequency of the vibration of your bike is far below the natural frequency of the bags, the forced oscillation on the bags is negligible. When you are speeding up to climb the slope, the frequency o…
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4ln(x) - 3ln(x + 1) + 2ln(x + 4) = ln(x⁴) - ln[(x + 1)³] + ln[(x + 4)²] = ln[x⁴(x + 4)²/(x + 1)³]
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4ln(x) - 3ln(x + 1) + 2ln(x + 4) = ln(x⁴) - ln[(x + 1)³] + ln[(x + 4)²] = ln[x⁴(x + 4)²/(x + 1)³]
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E = mc² Hence E can be measured in kg.m²/s² (= joule)
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5 + 5lnx = 20 5lnx = 15 lnx = 3 x = e³
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5 + 5lnx = 20 5lnx = 15 lnx = 3 x = e³
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Let's denote the magnitude of a vector V by |V| Given: |A + B| = n|A - B| Squaring both sides: |A + B|² = n²|A - B|² Since V² = |V|², (A + B)² = n²(A - B)² Performing the operation on vectors: A² + 2AB + B² = n²(A² - 2AB + B²) |A| = |B|==…
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Let's denote the magnitude of a vector V by |V| Given: |A + B| = n|A - B| Squaring both sides: |A + B|² = n²|A - B|² Since V² = |V|², (A + B)² = n²(A - B)² Performing the operation on vectors: A² + 2AB + B² = n²(A² - 2AB + B²) |A| = |B|==…
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F(x) is the value of the function when the variable receives the value x. When the variable increases by h, its new value is x + h, and your teacher asked you to evaluate the corresponding value of the function. If F(x) = 2x + 1, then F(x+h) =…
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cos2x - 4cosx - 5 = 0 2cos²x - 1 - 4cosx - 5 = 0 2cos²x - 4cosx - 6 = 0 cos²x - 2cosx - 3 = 0 (cosx + 1)(cosx - 3) = 0 cosx - 3 ≠ 0 Hence cosx + 1 = 0 cosx = -1 x = (2k + 1)π