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• v = -2i + 5j w = 3i + 4j (1/2)v = -i + (5/2)j w - v = 5i - j w = √(3i + 4j)^2 = 5 v_hat = (-2i + 5j) / √(2^2 + 5^2) = -.371i + .928j Not too confident about the last one.

  in How to do this calculus problem? Comment by anon-e-moose- June 2021
• v = -2i + 5j w = 3i + 4j (1/2)v = -i + (5/2)j w - v = 5i - j w = √(3i + 4j)^2 = 5 v_hat = (-2i + 5j) / √(2^2 + 5^2) = -.371i + .928j Not too confident about the last one.

  in How to do this calculus problem? Comment by anon-e-moose- June 2021
• c = f(a²-b², 4ab) let u(a,b) = a²-b² let v(a,b) = 4ab ∂u/∂a = 2a ∂v/∂a = 4b ∂c/∂a = ∂f(u,v)/∂a ∂c/∂a = ∂f(u,v)/∂u * ∂u/∂a + ∂f(u,v)/∂v * ∂v/∂a ∂c/∂a = ∂f(u,v)/∂u * 2a + ∂f(u,v)/∂v * 4b…

  in Calculus 3 problem partial derivatives? Comment by anon-e-moose- May 2021
• c = f(a²-b², 4ab) let u(a,b) = a²-b² let v(a,b) = 4ab ∂u/∂a = 2a ∂v/∂a = 4b ∂c/∂a = ∂f(u,v)/∂a ∂c/∂a = ∂f(u,v)/∂u * ∂u/∂a + ∂f(u,v)/∂v * ∂v/∂a ∂c/∂a = ∂f(u,v)/∂u * 2a + ∂f(u,v)/∂v * 4b…

  in Calculus 3 problem partial derivatives? Comment by anon-e-moose- May 2021
• v² = v_0² + 2ax (55)² = 0² + 2a*1 a = 1512.5 mi/h² v = v_0 + at 55 = 0 + 1512.5*t t = 0.0363756614 hours = 2.1825 minutes = 2:11

  in a car accelerates from zero to 55MPH? Comment by anon-e-moose- May 2021
• v² = v_0² + 2ax (55)² = 0² + 2a*1 a = 1512.5 mi/h² v = v_0 + at 55 = 0 + 1512.5*t t = 0.0363756614 hours = 2.1825 minutes = 2:11

  in a car accelerates from zero to 55MPH? Comment by anon-e-moose- May 2021
• v² = v_0² + 2ax (55)² = 0² + 2a*1 a = 1512.5 mi/h² v = v_0 + at 55 = 0 + 1512.5*t t = 0.0363756614 hours = 2.1825 minutes = 2:11

  in a car accelerates from zero to 55MPH? Comment by anon-e-moose- May 2021
• c = f(a²-b², 4ab) let u(a,b) = a²-b² let v(a,b) = 4ab ∂u/∂a = 2a ∂v/∂a = 4b ∂c/∂a = ∂f(u,v)/∂a ∂c/∂a = ∂f(u,v)/∂u * ∂u/∂a + ∂f(u,v)/∂v * ∂v/∂a ∂c/∂a = ∂f(u,v)/∂u * 2a + ∂f(u,v)/∂v * 4b…

  in Calculus 3 problem partial derivatives? Comment by anon-e-moose- May 2021