Default Avatar

andy-j

andy-j

About

Username
andy-j
Joined
Visits
0
Last Active
Roles
Member

Comments

  • Let d be the distance one way to the conference. Remember, d = rt. The distance both ways is the same: 54t1 = 45t2 Knowing that t1 + t2 = 11, we can substitute 11-t1 for t2: 54t1 = 45(11 - t1) 54t1 = 495 - 45t1 99t1 = 495 t1 = 5 Thus …
  • Do what I did and delete your page. Facebook is worthless and it only continues our social denigration.
  • What a good question indeed. I feel that this is all to do with gravity and weight of both objects. I think the answer would have to be that the cat will land on its feet as it is heavier than the toast. However, there is another possibility: If …
  • It's not terribly hard, but involved a lot of busy work. Start by writing the prime factorization integers 2-40. For instance: 40 = 2^3 * 5 39 = 3 * 13 ... Then multiply all the factors together. That means adding the exponents of all the pr…
  • It's not terribly hard, but involved a lot of busy work. Start by writing the prime factorization integers 2-40. For instance: 40 = 2^3 * 5 39 = 3 * 13 ... Then multiply all the factors together. That means adding the exponents of all the pr…
  • I do it all the time, we cant help it!! My BF doesn't care coz he's use to it, and we just carry on like nothing has happened, but i still get a little embarrassed.x x
  • I do it all the time, we cant help it!! My BF doesn't care coz he's use to it, and we just carry on like nothing has happened, but i still get a little embarrassed.x x
  • It's not terribly hard, but involved a lot of busy work. Start by writing the prime factorization integers 2-40. For instance: 40 = 2^3 * 5 39 = 3 * 13 ... Then multiply all the factors together. That means adding the exponents of all the pr…
  • It's not terribly hard, but involved a lot of busy work. Start by writing the prime factorization integers 2-40. For instance: 40 = 2^3 * 5 39 = 3 * 13 ... Then multiply all the factors together. That means adding the exponents of all the pr…
  • What a good question indeed. I feel that this is all to do with gravity and weight of both objects. I think the answer would have to be that the cat will land on its feet as it is heavier than the toast. However, there is another possibility: If …
  • Do what I did and delete your page. Facebook is worthless and it only continues our social denigration.
  • Let d be the distance one way to the conference. Remember, d = rt. The distance both ways is the same: 54t1 = 45t2 Knowing that t1 + t2 = 11, we can substitute 11-t1 for t2: 54t1 = 45(11 - t1) 54t1 = 495 - 45t1 99t1 = 495 t1 = 5 Thus …