Would someone be so kind as to explain to me how to get 40! as a product of primes?
(like 2^a 3^b 5^c etc...)
It's not terribly hard, but involved a lot of busy work. Start by writing the prime factorization integers 2-40. For instance:
40 = 2^3 * 5
39 = 3 * 13
...
Then multiply all the factors together. That means adding the exponents of all the primes.
Comments
It's not terribly hard, but involved a lot of busy work. Start by writing the prime factorization integers 2-40. For instance:
40 = 2^3 * 5
39 = 3 * 13
...
Then multiply all the factors together. That means adding the exponents of all the primes.