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• 1) let n = nickels, d = dimes, and q = quarters d = 2q --> 1/2d = q n = 7 + d 3.10 = .1d + .05n + .25q --> 3.10 = .1d + .05(7+d) + .25(d/2) --> 310 = 10d + 35 + 5d + 25/2d --> 275 = 27.5d --> d = 10 --> n = 17 --> q = …

  in College Algebra Math word problem? Comment by zylch May 2021
• 1) let n = nickels, d = dimes, and q = quarters d = 2q --> 1/2d = q n = 7 + d 3.10 = .1d + .05n + .25q --> 3.10 = .1d + .05(7+d) + .25(d/2) --> 310 = 10d + 35 + 5d + 25/2d --> 275 = 27.5d --> d = 10 --> n = 17 --> q = …

  in College Algebra Math word problem? Comment by zylch May 2021