yop-x
yop-x
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Es una buena idea la que te dá Sergio... Obtengamos unos pequeños resultados: Pr.1) ( 1 - r )( 1 + r + r² + r³ + ... + rⁿ ) = 1 - r^(n + 1) Esq Dem: ( 1 - r )( 1 + r + r² + r³ + ... + rⁿ ) = ( 1 + r + r² + r³ + ... + rⁿ ) - (r + rÂ…