woodsman
woodsman
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Their relative velocity is 140 mph, so the time it takes for them to meet is t = d / v = 105mi / 140mi/h = 0.75 hr Distance from Prospect Ave is d = v * t = 75mi/h * 0.75h = 56 mi
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Their relative velocity is 140 mph, so the time it takes for them to meet is t = d / v = 105mi / 140mi/h = 0.75 hr Distance from Prospect Ave is d = v * t = 75mi/h * 0.75h = 56 mi
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begin by recognizing that 3^(2x) = (3^x)^2 Now you can set z = 3^x and substitute z^2 - 12z + 27 = 0 is a standard quadratic (z - 3)(z - 9) = 0 (could use quadratic eqn to solve, would yield this result) substituting back in for z, we have th…
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begin by recognizing that 3^(2x) = (3^x)^2 Now you can set z = 3^x and substitute z^2 - 12z + 27 = 0 is a standard quadratic (z - 3)(z - 9) = 0 (could use quadratic eqn to solve, would yield this result) substituting back in for z, we have th…
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Their relative velocity is 140 mph, so the time it takes for them to meet is t = d / v = 105mi / 140mi/h = 0.75 hr Distance from Prospect Ave is d = v * t = 75mi/h * 0.75h = 56 mi
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Their relative velocity is 140 mph, so the time it takes for them to meet is t = d / v = 105mi / 140mi/h = 0.75 hr Distance from Prospect Ave is d = v * t = 75mi/h * 0.75h = 56 mi