tony-white_60a491af011db
tony-white_60a491af011db
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Oi Moises, Formamos um triangulo retangulo.... Portanto, o comprimento da hipotenusa apos 3 horas = 150km.... Dai o comprimento do cateto oposto = sen30 = xkm / 150km.. Entao...150sen30 = 75km..que e a distancia entre o ponto B e o movel…