Comments

• I assume you meant ∫ e^(x) dx / [1 + e^(x)] Let u = 1 + e^(x), du = e^(x) dx ∫ e^(x) dx / [1 + e^(x)] = ∫ du / u = ln(u) + C = ln(1 + e^(x)) + C

  in how do you integrate e^x/1+e^x dx? Comment by tom-marshall_60b8c1851c8f4 June 2021