theo-davies_60955cb5082b4
theo-davies_60955cb5082b4
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f(1) = 1² - 1 = 1 - 1 = 0 3.f(-1) = 3.[ (-1)² - (-1) ] = 3.[ 1 + 1 ] = 3 . 2 = 6 5.f(3) = 5.( 3² - 3 ) = 5.( 9 - 3 ) = 5. 6 = 30 f(0) = 0² - 0 = 0 - 0 = 0 Portanto f(1) + 3f(-1) - 5f(3) + f(0) = = 0 + 6 - 30 + 0 = - 24 …