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themurph2000

themurph2000

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themurph2000
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  • Easy. The opposing sides of parallelograms have to have the same length. So you have 2 sides with a length of 10. The other sides we'll call x. x + x + 10 + 10 = 48 2x + 20 = 48. Subtracting 20 from both sides... 2x = 28. Dividing both…
    in perimeter and a parallelogram? Comment by themurph2000 May 2021
  • Easy. The opposing sides of parallelograms have to have the same length. So you have 2 sides with a length of 10. The other sides we'll call x. x + x + 10 + 10 = 48 2x + 20 = 48. Subtracting 20 from both sides... 2x = 28. Dividing both…
    in perimeter and a parallelogram? Comment by themurph2000 May 2021
  • Easy. The opposing sides of parallelograms have to have the same length. So you have 2 sides with a length of 10. The other sides we'll call x. x + x + 10 + 10 = 48 2x + 20 = 48. Subtracting 20 from both sides... 2x = 28. Dividing both…
    in perimeter and a parallelogram? Comment by themurph2000 May 2021