technobuff
technobuff
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Time to drop 125m = sqrt. (2h/9.8) secs., = 5.05 secs. Time for sound to reach ears = (125/343) = .364 secs. (5.05 + .364) = 5.414 secs.
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Time to drop 125m = sqrt. (2h/9.8) secs., = 5.05 secs. Time for sound to reach ears = (125/343) = .364 secs. (5.05 + .364) = 5.414 secs.
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If you let the gas out, the compressor CANNOT run. There is a pressure switch in the system.
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If you let the gas out, the compressor CANNOT run. There is a pressure switch in the system.
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Velocity = sqrt.(2ad), = 113.189m/sec. Vi^2 = Vf^2 + 2ad. Vf = sqrt.(Vi^2 - 2ad) = sqrt.113.189^2 - (2(5.51 x 331)), = 95.73m/sec.
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If there are 2011 contact points, there are 2010 resistances in a circuit. The resistance between any 2 adjacent points is R/2010. No idea what you mean by N-2 points. The current is the same through all 2010 resistances, but the applied PD acro…
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a. They are both in the same direction. b. They are at 90 deg. to each other. c. They are at 180 deg. to each other.
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a. They are both in the same direction. b. They are at 90 deg. to each other. c. They are at 180 deg. to each other.
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A transistor is biassed to allow it to faithfully amplify a signal without distortion. It also sets a "minimum" DC level for an input AC signal, and the AC level is such that when the voltage rises to peak, it remains within the "line…
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"Some sort of a pulley system" does not adequately explain what you want. Can you describe better what you are wanting to do, and specify what power source you want to use? The weigh of the "object" could also help, the height…
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"Some sort of a pulley system" does not adequately explain what you want. Can you describe better what you are wanting to do, and specify what power source you want to use? The weigh of the "object" could also help, the height…
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"Some sort of a pulley system" does not adequately explain what you want. Can you describe better what you are wanting to do, and specify what power source you want to use? The weigh of the "object" could also help, the height…
-
A transistor is biassed to allow it to faithfully amplify a signal without distortion. It also sets a "minimum" DC level for an input AC signal, and the AC level is such that when the voltage rises to peak, it remains within the "line…
-
a. They are both in the same direction. b. They are at 90 deg. to each other. c. They are at 180 deg. to each other.
-
a. They are both in the same direction. b. They are at 90 deg. to each other. c. They are at 180 deg. to each other.
-
a. They are both in the same direction. b. They are at 90 deg. to each other. c. They are at 180 deg. to each other.
-
a. They are both in the same direction. b. They are at 90 deg. to each other. c. They are at 180 deg. to each other.
-
If there are 2011 contact points, there are 2010 resistances in a circuit. The resistance between any 2 adjacent points is R/2010. No idea what you mean by N-2 points. The current is the same through all 2010 resistances, but the applied PD acro…
-
If there are 2011 contact points, there are 2010 resistances in a circuit. The resistance between any 2 adjacent points is R/2010. No idea what you mean by N-2 points. The current is the same through all 2010 resistances, but the applied PD acro…
-
If there are 2011 contact points, there are 2010 resistances in a circuit. The resistance between any 2 adjacent points is R/2010. No idea what you mean by N-2 points. The current is the same through all 2010 resistances, but the applied PD acro…
-
If there are 2011 contact points, there are 2010 resistances in a circuit. The resistance between any 2 adjacent points is R/2010. No idea what you mean by N-2 points. The current is the same through all 2010 resistances, but the applied PD acro…
-
If there are 2011 contact points, there are 2010 resistances in a circuit. The resistance between any 2 adjacent points is R/2010. No idea what you mean by N-2 points. The current is the same through all 2010 resistances, but the applied PD acro…
-
Velocity = sqrt.(2ad), = 113.189m/sec. Vi^2 = Vf^2 + 2ad. Vf = sqrt.(Vi^2 - 2ad) = sqrt.113.189^2 - (2(5.51 x 331)), = 95.73m/sec.
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Velocity = sqrt.(2ad), = 113.189m/sec. Vi^2 = Vf^2 + 2ad. Vf = sqrt.(Vi^2 - 2ad) = sqrt.113.189^2 - (2(5.51 x 331)), = 95.73m/sec.
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If you let the gas out, the compressor CANNOT run. There is a pressure switch in the system.
-
If you let the gas out, the compressor CANNOT run. There is a pressure switch in the system.
-
Time to drop 125m = sqrt. (2h/9.8) secs., = 5.05 secs. Time for sound to reach ears = (125/343) = .364 secs. (5.05 + .364) = 5.414 secs.