sophie-baker_60c1ff4408c67
sophie-baker_60c1ff4408c67
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a) gof = g(f(x)) = 3, isso pq independente do valor de x, o g(x) será 3 b) fog = f(x) = x², sendo x = g(x), temos que f(g(x))= (valor de g(x), elevado ao quadrado), portanto fog = f(g(x)) = 3² = 9