shadowblues
shadowblues
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First factor out a 2 to get 8x^3+27. This is now a sum of cubes therefore, 8x^3 is 2x and the cube of 27 is three. (2x+3), now factor the rest to be2 (2x+3)(4x^2-6x-9) the standard form of the sum of cubes is (a + b)(a^2 - 2b - b^2)
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First factor out a 2 to get 8x^3+27. This is now a sum of cubes therefore, 8x^3 is 2x and the cube of 27 is three. (2x+3), now factor the rest to be2 (2x+3)(4x^2-6x-9) the standard form of the sum of cubes is (a + b)(a^2 - 2b - b^2)