Comments

• let´s speak of mm of rainfall .These are just plain mm and refer to a prisma with a base of 1m^2 and height the mm. So they come up to a volume in which 1mm= 1liter/m^2.So take the surface of your tank in square meter and multiply it by the mm of r…

  in Geometry/Algebra problem? Comment by santmann2002 June 2021
• let´s speak of mm of rainfall .These are just plain mm and refer to a prisma with a base of 1m^2 and height the mm. So they come up to a volume in which 1mm= 1liter/m^2.So take the surface of your tank in square meter and multiply it by the mm of r…

  in Geometry/Algebra problem? Comment by santmann2002 June 2021
• Take ln of both sides 0.006x =ln30 x= (ln30)/0.006 =566.87

  in how do I solve this natural logarithm problem? Comment by santmann2002 June 2021
• using implicit derivative 2*y*y'=y+x*y' so y'= y/(2y-x) =1/2 so 2y= 2y-x and x=0 and y =+-sqrt2 y'=0 provides y=0 and 0=2 absurd there are no points with horizontal tangent if it were verticla tangent x=2y and y^2= 2+2y^2 and y^=-2 impossible d…

  in Calculus problem help, please? Comment by santmann2002 May 2021
• One roor is 3 so you should find the other factor dividing by (x-3) x^3-27 = (x-3)*(x^2+3x+9)

  in How do you factor X^3 - 27?? Comment by santmann2002 May 2021
• One roor is 3 so you should find the other factor dividing by (x-3) x^3-27 = (x-3)*(x^2+3x+9)

  in How do you factor X^3 - 27?? Comment by santmann2002 May 2021
• Take ln y= sinx)^2sinx) lny = 2 sin x * ln sin x y´/y= 2[cosx*ln sin x +sin x*1/sinx *cos x) so y´= (sin x)^2 sin x * cos x( ln sin x +1)*2

  in derivatives dy/dx of y=(sinx)^(2sinx)? Comment by santmann2002 May 2021
• f´(x) = 2/cos(x) * (-sin x)

  in f(x)=2 ln [cosx]? Comment by santmann2002 May 2021
• f´(x) = 2/cos(x) * (-sin x)

  in f(x)=2 ln [cosx]? Comment by santmann2002 May 2021
• Take ln y= sinx)^2sinx) lny = 2 sin x * ln sin x y´/y= 2[cosx*ln sin x +sin x*1/sinx *cos x) so y´= (sin x)^2 sin x * cos x( ln sin x +1)*2

  in derivatives dy/dx of y=(sinx)^(2sinx)? Comment by santmann2002 May 2021
• One roor is 3 so you should find the other factor dividing by (x-3) x^3-27 = (x-3)*(x^2+3x+9)

  in How do you factor X^3 - 27?? Comment by santmann2002 May 2021
• using implicit derivative 2*y*y'=y+x*y' so y'= y/(2y-x) =1/2 so 2y= 2y-x and x=0 and y =+-sqrt2 y'=0 provides y=0 and 0=2 absurd there are no points with horizontal tangent if it were verticla tangent x=2y and y^2= 2+2y^2 and y^=-2 impossible d…

  in Calculus problem help, please? Comment by santmann2002 May 2021