Comments

• no of equivalents of NaOH used =0.139*0.0239= 0.003322 therefore, no of equivalents of acid = .003322 no of equivalents * equivalent weight = mass of acid equivalent mass = 0.268/.00322 = 83.229g

  in how to do this chemistry problem? Comment by samiit05 May 2021
• no of equivalents of NaOH used =0.139*0.0239= 0.003322 therefore, no of equivalents of acid = .003322 no of equivalents * equivalent weight = mass of acid equivalent mass = 0.268/.00322 = 83.229g

  in how to do this chemistry problem? Comment by samiit05 May 2021
• no of equivalents of NaOH used =0.139*0.0239= 0.003322 therefore, no of equivalents of acid = .003322 no of equivalents * equivalent weight = mass of acid equivalent mass = 0.268/.00322 = 83.229g

  in how to do this chemistry problem? Comment by samiit05 May 2021
• no of equivalents of NaOH used =0.139*0.0239= 0.003322 therefore, no of equivalents of acid = .003322 no of equivalents * equivalent weight = mass of acid equivalent mass = 0.268/.00322 = 83.229g

  in how to do this chemistry problem? Comment by samiit05 May 2021