ruth-roberts_60bea71e5a764
ruth-roberts_60bea71e5a764
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mozart merece essa pois a sua resolução está correta! 3x² = 0 --> x' = x" = 0 x² = 49 --> x = +/-\/49 --> x = +/-7 3x²-x+1=0 delta = (-1)²-4.3.1 delta = 1+12 delta = 13 x = (-b+/-\/delta)/2a x = (-(-1)+/-\/13)/2 x' = (1+…