rowena-lewis_60b93c8449e3f
rowena-lewis_60b93c8449e3f
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a) 200 ml em água tem 0,200 kg E = mc θ Δ , sendo m = 0,2 kg e c = 4,0 . 10³ J/KgºC Logo E = 0,2 . 4,0 . 103 . 75 ⇒ E = 6,0 . 10^4 J b) Tempo de aquecimento, Δ t. E = P Δt e P = Ui. Logo E = Ui Δt assim 6,0 . 10^4 = 120 . 5,0 Δt ⇒ 100s