Comments

• I just answered this very problem for agape: http://answers.yahoo.com/question/index;_ylt=Aoekw... In fact, both have "pistol" instead of "piston", so I suspect you and agape are the same person. If so, please do not post a pr…

  in Derivatives problem...word...? Comment by ron-w June 2021
• I just answered this very problem for agape: http://answers.yahoo.com/question/index;_ylt=Aoekw... In fact, both have "pistol" instead of "piston", so I suspect you and agape are the same person. If so, please do not post a pr…

  in Derivatives problem...word...? Comment by ron-w June 2021
• Complete the square in the denominator: x² - 4x + 5 = x² - 4x + 4 + 1 = (x-2)² + 1 So ∫ dx/(x² - 4x + 5) = ∫ dx/[(x-2)² + 1] = arctan(x-2) where the integral has lower limit 1 and upper limit ∞. The integral is bounded, so the sum con…

  in Series convergent or divergent? Comment by ron-w June 2021
• The first sentence translates almost verbatim to x = 2+ 3y If 10x + y is the original number, then 10y + x is the number resulting from interchanging the digits. The second sentence says 10y + x = ½(10x + y) - 13 Multiply both sides of th…

  in Algebra 2 word problem help ? Comment by ron-w June 2021
• No, the two sides are not equal. The right side is the first term of the expansion of the left side. The right side also needs the term + e^(-x) sin(2x) to have equality.

  in Does (e^(-x))(-2cos(2x)+sin(2x)) =( -2e^(-x)) cox (2x).? Comment by ron-w May 2021
• No, the two sides are not equal. The right side is the first term of the expansion of the left side. The right side also needs the term + e^(-x) sin(2x) to have equality.

  in Does (e^(-x))(-2cos(2x)+sin(2x)) =( -2e^(-x)) cox (2x).? Comment by ron-w May 2021
• A trip of x miles is a trip of 4x quarter-miles, right? The first quarter-mile costs c cents, and the other (4x-1) cost s cents each. So the total cost is c + s(4x-1) Answer is A.

  in Math Problem...? Comment by ron-w May 2021
• A trip of x miles is a trip of 4x quarter-miles, right? The first quarter-mile costs c cents, and the other (4x-1) cost s cents each. So the total cost is c + s(4x-1) Answer is A.

  in Math Problem...? Comment by ron-w May 2021
• A trip of x miles is a trip of 4x quarter-miles, right? The first quarter-mile costs c cents, and the other (4x-1) cost s cents each. So the total cost is c + s(4x-1) Answer is A.

  in Math Problem...? Comment by ron-w May 2021
• No, the two sides are not equal. The right side is the first term of the expansion of the left side. The right side also needs the term + e^(-x) sin(2x) to have equality.

  in Does (e^(-x))(-2cos(2x)+sin(2x)) =( -2e^(-x)) cox (2x).? Comment by ron-w May 2021
• The first sentence translates almost verbatim to x = 2+ 3y If 10x + y is the original number, then 10y + x is the number resulting from interchanging the digits. The second sentence says 10y + x = ½(10x + y) - 13 Multiply both sides of th…

  in Algebra 2 word problem help ? Comment by ron-w May 2021
• Complete the square in the denominator: x² - 4x + 5 = x² - 4x + 4 + 1 = (x-2)² + 1 So ∫ dx/(x² - 4x + 5) = ∫ dx/[(x-2)² + 1] = arctan(x-2) where the integral has lower limit 1 and upper limit ∞. The integral is bounded, so the sum con…

  in Series convergent or divergent? Comment by ron-w May 2021
• I just answered this very problem for agape: http://answers.yahoo.com/question/index;_ylt=Aoekw... In fact, both have "pistol" instead of "piston", so I suspect you and agape are the same person. If so, please do not post a pr…

  in Derivatives problem...word...? Comment by ron-w May 2021