rohan1990
rohan1990
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If total time is 2.5 secs then time from ground to highest point is 1.25 seconds. v = u-gt 0 = u - 32*1.25 so initial speed is 40 ft/ sec substitute in x = ut - (0.5)g(t^2) = (40*1.25) - (0.5)(32)(1.25^2) …
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If total time is 2.5 secs then time from ground to highest point is 1.25 seconds. v = u-gt 0 = u - 32*1.25 so initial speed is 40 ft/ sec substitute in x = ut - (0.5)g(t^2) = (40*1.25) - (0.5)(32)(1.25^2) …