robson-amaral
robson-amaral
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tg = cateto oposto/cateto adjascente tg60° = 5/x â3 = 5/x xâ3 = 5 x = 5/â3 x= 5/â3 * â3/â3 x = (5â3)/(â3*â3) x = (5â3)/3 espero ter ajudado