Comments

• BC=6 B=30° C=45° A=180°-(30+45)=105° h=x.sen 30° h=(6-x).sen 45° x.sen 30°= (6-x). sen 45° x.sen 30°= 6.sen 45°-x.sen 45° x.sen 30°+x.sen 45°=6.sen 45° x.(sen 30°+sen 45°)=6.sen 45° x=(6.(²V2/2))/((²V3/2)+(²V2/2)) x=…

  in Calcular a altura relativa ao lado BC.? Comment by rob-young_60b6d04e452bb June 2021