rob-rogers_60aee2f73e625
rob-rogers_60aee2f73e625
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√ α 3º Quadrante: tg: + sen: - cos: - tgα = 2 senα / cosα = 2 ----> cosα = senα/2 sen²α + cos²α = 1 sen²α + (senα/2)² = 1 sen²α + sen²α/4 = 1 4sen²α + sen²α = 4 5sen²α = 4 senα = - √4 / √5 senα = -2/ √5 = -2√5 / 5