rob-parker_60c21b09bb44c
rob-parker_60c21b09bb44c
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f(x) = (x + 1) . (x² + ax + b) A(1,0) e B(0,5) pertencem a f(x) ---> A: f(1) = 2.(1 + a + b) = 2 + 2a + 2b = 0 ---> a + b = -1 .....................................................B: f(0) = 1.(0 + 0 + b) = b = 5 -----> b = 5 Resolven…